如何对数字进行预排序而不搞砸格式?
How do I pre-sort numbers and not screw up the formatting?
我正在编写一个自定义函数,它将 return 一个数组数组:
function tester(col){
var rows = [ // this gives me an error on sorting, so turn numbers to strings
[4,2,3,"Tom"],
[0,8,9,"Bill"],
[5,7,1,"Bob"],
[1,2,3,"Charlie"]
];
rows = [ // turning numbers to strings screws up formatting
["4","2","3","Tom"],
["0","8","9","Bill"],
["5","7","1","Bob"],
["1","2","3","Charlie"]
];
rows.sort(function(a, b) {
return a[col].localeCompare(b[col]); // sort by column passed by user
});
return rows;
}
如前所述,如果我传入数字,则会出现错误:
TypeError: Cannot find function localCompare in object
如果我将这些数字转换为字符串,我可以排序,但用户无法设置数字的格式...显示更多小数、逗号,将它们转换为百分比等。我该如何解决这个问题?
编辑:
我试过 Buzinas/Kriggs 的建议,但它似乎对数字和负数进行了词法排序,而其他排序不正确。我现在有(注意负数 4 和 750):
function tester(col){
var rows = [
[-4,2,3,"Tom"],
[0,8,9,"Bill"],
[5,750,1,"Bob"],
[1,2,3,"Charlie"]
];
rows.sort(function(a, b) {
return a[col].toString().localeCompare(b[col].toString());
});
return rows;
}
更新
如果是数字要按数字排序,如果是字符串要按字符串排序,可以这样做:
function tester(col){
var rows = [
[4,2,3,"Tom"],
[0,8,9,"Bill"],
[5,7,1,"Bob"],
[1,2,3,"Charlie"]
];
rows.sort(function(a, b) {
if (typeof a[col] === 'number')
return a[col] > b[col];
return a[col].localeCompare(b[col]);
});
return rows;
}
我正在编写一个自定义函数,它将 return 一个数组数组:
function tester(col){
var rows = [ // this gives me an error on sorting, so turn numbers to strings
[4,2,3,"Tom"],
[0,8,9,"Bill"],
[5,7,1,"Bob"],
[1,2,3,"Charlie"]
];
rows = [ // turning numbers to strings screws up formatting
["4","2","3","Tom"],
["0","8","9","Bill"],
["5","7","1","Bob"],
["1","2","3","Charlie"]
];
rows.sort(function(a, b) {
return a[col].localeCompare(b[col]); // sort by column passed by user
});
return rows;
}
如前所述,如果我传入数字,则会出现错误:
TypeError: Cannot find function localCompare in object
如果我将这些数字转换为字符串,我可以排序,但用户无法设置数字的格式...显示更多小数、逗号,将它们转换为百分比等。我该如何解决这个问题?
编辑:
我试过 Buzinas/Kriggs 的建议,但它似乎对数字和负数进行了词法排序,而其他排序不正确。我现在有(注意负数 4 和 750):
function tester(col){
var rows = [
[-4,2,3,"Tom"],
[0,8,9,"Bill"],
[5,750,1,"Bob"],
[1,2,3,"Charlie"]
];
rows.sort(function(a, b) {
return a[col].toString().localeCompare(b[col].toString());
});
return rows;
}
更新
如果是数字要按数字排序,如果是字符串要按字符串排序,可以这样做:
function tester(col){
var rows = [
[4,2,3,"Tom"],
[0,8,9,"Bill"],
[5,7,1,"Bob"],
[1,2,3,"Charlie"]
];
rows.sort(function(a, b) {
if (typeof a[col] === 'number')
return a[col] > b[col];
return a[col].localeCompare(b[col]);
});
return rows;
}