使用 2 个 ORDER BY 语句的 COUNT 中没有零值

No zero values in COUNT with 2 ORDER BY statments

我有 3 个表:

+---------+    +----------+    +----------+
|  kkw    |    |  block   |    |  status  |
+---------+    +----------+    +----------+
| kkw_id  |    | block_id |    |status_id |
| land_id |    | kkw_id   |    | ....     |
| ...     |    | status_id|    | ....     |
+---------+    +----------+    +----------+

我想显示每个国家(land_id)和状态的块数,如果一个国家没有与状态对应的块,则为零。我尝试了这个请求,但没有显示零值:

SELECT s.status_id, k.land_id, COUNT(b.block_id)
FROM kkw_status AS s
LEFT JOIN block AS b ON s.status_id = b.status_id
LEFT JOIN kkw AS k ON b.kkw_id=k.kkw_id
GROUP BY s.status_id, k.land_id
ORDER BY k.land_id, s.status_id;

结果:

status_id   land_id count
    1          1      2
    4          1      3  ....

但我想:

status_id   land_id count
    1          1      2
    2          1      0
    3          1      0
    4          1      3  .....

有什么想法吗?谢谢

您正在按 k.land_id 分组。因此,当某些内容不匹配时,它会为该列获取 NULL 的值。因此,零值只会出现在此类行上。

如果您想要所有 status_idland_id,请使用 cross join 创建所有这些的列表,然后计算与每个组匹配的数字。我认为这就是查询的样子:

SELECT s.status_id, k.land_id, COUNT(b.block_id)
FROM kkw_status s CROSS JOIN
     kkw k LEFT JOIN
     block b
     ON b.status_id = s.status_id AND b.kkw_id = k.kkw_id
GROUP BY s.status_id, k.land_id
ORDER BY k.land_id, s.status_id;