使用 2 个 ORDER BY 语句的 COUNT 中没有零值
No zero values in COUNT with 2 ORDER BY statments
我有 3 个表:
+---------+ +----------+ +----------+
| kkw | | block | | status |
+---------+ +----------+ +----------+
| kkw_id | | block_id | |status_id |
| land_id | | kkw_id | | .... |
| ... | | status_id| | .... |
+---------+ +----------+ +----------+
我想显示每个国家(land_id)和状态的块数,如果一个国家没有与状态对应的块,则为零。我尝试了这个请求,但没有显示零值:
SELECT s.status_id, k.land_id, COUNT(b.block_id)
FROM kkw_status AS s
LEFT JOIN block AS b ON s.status_id = b.status_id
LEFT JOIN kkw AS k ON b.kkw_id=k.kkw_id
GROUP BY s.status_id, k.land_id
ORDER BY k.land_id, s.status_id;
结果:
status_id land_id count
1 1 2
4 1 3 ....
但我想:
status_id land_id count
1 1 2
2 1 0
3 1 0
4 1 3 .....
有什么想法吗?谢谢
您正在按 k.land_id
分组。因此,当某些内容不匹配时,它会为该列获取 NULL
的值。因此,零值只会出现在此类行上。
如果您想要所有 status_id
和 land_id
,请使用 cross join
创建所有这些的列表,然后计算与每个组匹配的数字。我认为这就是查询的样子:
SELECT s.status_id, k.land_id, COUNT(b.block_id)
FROM kkw_status s CROSS JOIN
kkw k LEFT JOIN
block b
ON b.status_id = s.status_id AND b.kkw_id = k.kkw_id
GROUP BY s.status_id, k.land_id
ORDER BY k.land_id, s.status_id;
我有 3 个表:
+---------+ +----------+ +----------+
| kkw | | block | | status |
+---------+ +----------+ +----------+
| kkw_id | | block_id | |status_id |
| land_id | | kkw_id | | .... |
| ... | | status_id| | .... |
+---------+ +----------+ +----------+
我想显示每个国家(land_id)和状态的块数,如果一个国家没有与状态对应的块,则为零。我尝试了这个请求,但没有显示零值:
SELECT s.status_id, k.land_id, COUNT(b.block_id)
FROM kkw_status AS s
LEFT JOIN block AS b ON s.status_id = b.status_id
LEFT JOIN kkw AS k ON b.kkw_id=k.kkw_id
GROUP BY s.status_id, k.land_id
ORDER BY k.land_id, s.status_id;
结果:
status_id land_id count
1 1 2
4 1 3 ....
但我想:
status_id land_id count
1 1 2
2 1 0
3 1 0
4 1 3 .....
有什么想法吗?谢谢
您正在按 k.land_id
分组。因此,当某些内容不匹配时,它会为该列获取 NULL
的值。因此,零值只会出现在此类行上。
如果您想要所有 status_id
和 land_id
,请使用 cross join
创建所有这些的列表,然后计算与每个组匹配的数字。我认为这就是查询的样子:
SELECT s.status_id, k.land_id, COUNT(b.block_id)
FROM kkw_status s CROSS JOIN
kkw k LEFT JOIN
block b
ON b.status_id = s.status_id AND b.kkw_id = k.kkw_id
GROUP BY s.status_id, k.land_id
ORDER BY k.land_id, s.status_id;