使用 XSLT 从 Excel XML 检索数据

Question

我有一个 excel 如下，其中第 5 行有 header 数据。

编辑：

输入excel也可能出现如下情况。数据可能出现在任何列中。数据必须使用行 headers 广告名称、UID 和 Status.It 不会更改。

然后保存为作业本xml如下

<?xml version="1.0"?>
<Workbook xmlns="urn:schemas-microsoft-com:office:spreadsheet"
 xmlns:o="urn:schemas-microsoft-com:office:office"
 xmlns:x="urn:schemas-microsoft-com:office:excel"
 xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet"
 xmlns:html="http://www.w3.org/TR/REC-html40">
 <DocumentProperties xmlns="urn:schemas-microsoft-com:office:office">
  <Author>Jefferson D</Author>
  <LastAuthor>Jefferson D</LastAuthor>
  <Created>2015-10-29T17:10:31Z</Created>
  <LastSaved>2015-10-29T17:15:02Z</LastSaved>
  <Company>*CL</Company>
  <Version>12.0</Version>
 </DocumentProperties>
 <OfficeDocumentSettings xmlns="urn:schemas-microsoft-com:office:office">
  <AllowPNG/>
 </OfficeDocumentSettings>
 <ExcelWorkbook xmlns="urn:schemas-microsoft-com:office:excel">
  <WindowHeight>22060</WindowHeight>
  <WindowWidth>34400</WindowWidth>
  <WindowTopX>-20</WindowTopX>
  <WindowTopY>-20</WindowTopY>
  <Date1904/>
  <ProtectStructure>False</ProtectStructure>
  <ProtectWindows>False</ProtectWindows>
 </ExcelWorkbook>
 <Styles>
  <Style ss:ID="Default" ss:Name="Normal">
   <Alignment ss:Vertical="Bottom"/>
   <Borders/>
   <Font ss:FontName="Verdana"/>
   <Interior/>
   <NumberFormat/>
   <Protection/>
  </Style>
  <Style ss:ID="s16">
   <Font ss:FontName="Verdana" ss:Bold="1"/>
  </Style>
 </Styles>
 <Worksheet ss:Name="Sheet1">
  <Table ss:ExpandedColumnCount="3" ss:ExpandedRowCount="10" x:FullColumns="1"
   x:FullRows="1">
   <Column ss:AutoFitWidth="0" ss:Width="176.0"/>
   <Column ss:AutoFitWidth="0" ss:Width="141.0"/>
   <Column ss:AutoFitWidth="0" ss:Width="152.0"/>
   <Row>
    <Cell ss:Index="2" ss:StyleID="s16"><Data ss:Type="String">Ad Report</Data></Cell>
   </Row>
   <Row ss:Index="3">
    <Cell><Data ss:Type="String">IssueNo: 1</Data></Cell>
   </Row>
   <Row>
    <Cell><Data ss:Type="String">IssueName: XXX</Data></Cell>
   </Row>
   <Row>
    <Cell><Data ss:Type="String">Issue Date: YYY</Data></Cell>
   </Row>
   <Row ss:StyleID="s16">
    <Cell><Data ss:Type="String">Ad Name</Data></Cell>
    <Cell><Data ss:Type="String">UID</Data></Cell>
    <Cell><Data ss:Type="String">Status</Data></Cell>
   </Row>
   <Row>
    <Cell><Data ss:Type="String">WWW</Data></Cell>
    <Cell><Data ss:Type="String">0A1</Data></Cell>
    <Cell><Data ss:Type="String">active</Data></Cell>
   </Row>
   <Row>
    <Cell><Data ss:Type="String">XXX</Data></Cell>
    <Cell><Data ss:Type="String">1B2</Data></Cell>
    <Cell><Data ss:Type="String">active</Data></Cell>
   </Row>
   <Row>
    <Cell><Data ss:Type="String">YYY</Data></Cell>
    <Cell><Data ss:Type="String">2C3</Data></Cell>
    <Cell><Data ss:Type="String">inactive</Data></Cell>
   </Row>
  </Table>
  <WorksheetOptions xmlns="urn:schemas-microsoft-com:office:excel">
   <Print>
    <ValidPrinterInfo/>
    <PaperSizeIndex>10</PaperSizeIndex>
    <HorizontalResolution>-4</HorizontalResolution>
    <VerticalResolution>-4</VerticalResolution>
   </Print>
   <ShowPageLayoutZoom/>
   <PageLayoutZoom>100</PageLayoutZoom>
   <Selected/>
   <Panes>
    <Pane>
     <Number>3</Number>
     <ActiveRow>13</ActiveRow>
     <ActiveCol>2</ActiveCol>
    </Pane>
   </Panes>
   <ProtectObjects>False</ProtectObjects>
   <ProtectScenarios>False</ProtectScenarios>
  </WorksheetOptions>
 </Worksheet>
</Workbook>

我想使用 XSLT2.0 从 Excel xml 文件中提取一些数据，并想创建一个新的 xml 作为关注

<adverts>
   <advert>
      <advertName>WWW</advertName>
      <advertNumber>0A1</advertNumber>
      <advertStatus>active<advertStatus>
   </advert>
   <advert>
      <advertName>XXX</advertName>
      <advertNumber>1B2</advertNumber>
      <advertStatus>active<advertStatus>
   </advert>
   <advert>
      <advertName>YYY</advertName>
      <advertNumber>2C3</advertNumber>
      <advertStatus>inactive<advertStatus>
   </advert>
</adverts>

我很困惑，因为这是我第一次处理工作簿XML。任何指导 link 也很可观。

Answer 1

编辑以回应澄清：

The data may appear in any column. The data has to be identified using the row headers Ad Name, UID and Status.

这样试试；

XSLT 2.0

<xsl:stylesheet version="2.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet"
exclude-result-prefixes="ss">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:variable name="rows" select="/ss:Workbook/ss:Worksheet/ss:Table/ss:Row" />
<xsl:variable name="header-row" select="$rows[ss:Cell/ss:Data='Ad Name'][1]" />
<xsl:variable name="header-row-num" select="index-of($rows, $header-row)" />

<xsl:variable name="header-row-cells" select="$header-row/ss:Cell" />
<xsl:variable name="name-col-num" select="index-of($header-row-cells, $header-row-cells[ss:Data='Ad Name'][1])" />
<xsl:variable name="number-col-num" select="index-of($header-row-cells, $header-row-cells[ss:Data='UID'][1])" />
<xsl:variable name="status-col-num" select="index-of($header-row-cells, $header-row-cells[ss:Data='Stattus'][1])" />

<xsl:template match="/ss:Workbook">
    <adverts>
        <xsl:apply-templates select="ss:Worksheet/ss:Table/ss:Row[position() gt $header-row-num]"/>
    </adverts>      
</xsl:template>

<xsl:template match="ss:Row">
    <advert>
        <advertName>
            <xsl:value-of select="ss:Cell[$name-col-num]/ss:Data"/>
        </advertName>
        <advertNumber>
            <xsl:value-of select="ss:Cell[$number-col-num]/ss:Data"/>
        </advertNumber>
        <advertStatus>
            <xsl:value-of select="ss:Cell[$status-col-num]/ss:Data"/>
        </advertStatus>
    </advert>
</xsl:template>

</xsl:stylesheet>

应用于您的XML输入示例，结果为：

<?xml version="1.0" encoding="UTF-8"?>
<adverts>
   <advert>
      <advertName>WWW</advertName>
      <advertNumber>0A1</advertNumber>
      <advertStatus>active</advertStatus>
   </advert>
   <advert>
      <advertName>XXX</advertName>
      <advertNumber>1B2</advertNumber>
      <advertStatus>active</advertStatus>
   </advert>
   <advert>
      <advertName>YYY</advertName>
      <advertNumber>2C3</advertNumber>
      <advertStatus>inactive</advertStatus>
   </advert>
</adverts>

注：

I have an excel as follows which has header data in 6th row.

与您在屏幕截图中所说和显示的相反，header 行在你的 XML 实际上是第 5 行，而不是第 6 行。样式表上面通过包含的单元格的存在来标识 header 行 "Ad Name"。如果你事先知道这个数字，你可以简化直接使用该数字的样式表；
在您的 XML 中，列名是 "Stattus' not "Status”。因此，上面的样式表查找 "Stattus" 以便 return处理您的 XML 示例时的预期结果。

使用 XSLT 从 Excel XML 检索数据

Retrieving data from Excel XML using XSLT

xml

xslt

excel

xlsx

xslt-2.0