如何从 onActivityResult Intent 获取视频缩略图?
How to Get Video Thumbnail from onActivityResult Intent?
下面是我的代码,我从 ThumbnailUtils.createVideoThumbnail
得到一个空值
Intent takePicture = new Intent(Intent.ACTION_PICK, MediaStore.Video.Media.EXTERNAL_CONTENT_URI);
takePicture.setType("video/*");
startActivityForResult(takePicture, 4);
我的视频文件选择意图的 OnResultActivity 代码:
if(requestCode == 4) {
Uri selectedVideoUri = data.getData();
Bitmap bitmap = ThumbnailUtils.createVideoThumbnail(selectedVideoUri.getPath(), MediaStore.Video.Thumbnails.MINI_KIND);
Log.i("Video URI, ", String.valueOf(bitmap));
}
另外请帮助我如何从录制的视频意图中获取缩略图
Intent takeVideo = new Intent(MediaStore.ACTION_VIDEO_CAPTURE);
startActivityForResult(takeVideo, REQUEST_VIDEO_CAPTURE);
经过一些研究,我注意到 file path 不应该是 uri
你应该有这样的东西
final String noturipath = getRealPathFromUri();
Bitmap bitmap = ThumbnailUtils.createVideoThumbnail(noturipath, MediaStore.Video.Thumbnails.MICRO_KIND);
然后创建一个方法
public string getRealPathFromUri (final Uri content)
{
// get intent from activity and added it here
Uri uri;
String stringUri;
stringUri = uri.toString();
}
下面是我的代码,我从 ThumbnailUtils.createVideoThumbnail
得到一个空值Intent takePicture = new Intent(Intent.ACTION_PICK, MediaStore.Video.Media.EXTERNAL_CONTENT_URI);
takePicture.setType("video/*");
startActivityForResult(takePicture, 4);
我的视频文件选择意图的 OnResultActivity 代码:
if(requestCode == 4) {
Uri selectedVideoUri = data.getData();
Bitmap bitmap = ThumbnailUtils.createVideoThumbnail(selectedVideoUri.getPath(), MediaStore.Video.Thumbnails.MINI_KIND);
Log.i("Video URI, ", String.valueOf(bitmap));
}
另外请帮助我如何从录制的视频意图中获取缩略图
Intent takeVideo = new Intent(MediaStore.ACTION_VIDEO_CAPTURE);
startActivityForResult(takeVideo, REQUEST_VIDEO_CAPTURE);
经过一些研究,我注意到 file path 不应该是 uri
你应该有这样的东西
final String noturipath = getRealPathFromUri();
Bitmap bitmap = ThumbnailUtils.createVideoThumbnail(noturipath, MediaStore.Video.Thumbnails.MICRO_KIND);
然后创建一个方法
public string getRealPathFromUri (final Uri content)
{
// get intent from activity and added it here
Uri uri;
String stringUri;
stringUri = uri.toString();
}