用字符串替换列表元素中的列表元素

Question

所以我正在尝试创建一个网格，可以用任何给定的符号替换它的单个 "grid squares"。网格工作正常，但它是由列表中的列表组成的。

这是代码

size = 49
feild = []
for i in range(size):
    feild.append([])
for i in range(size):
    feild[i].append("#")
feild[4][4] = "@" #This is one of the methods of replacing that I have tried
for i in range(size):
    p_feild = str(feild)
    p_feild2 = p_feild.replace("[", "")
    p_feild3 = p_feild2.replace("]", "")
    p_feild4 = p_feild3.replace(",", "")
    p_feild5 = p_feild4.replace("'", "")
    print(p_feild5)

如您所见，这是我尝试替换元素的一种方法，我也尝试过：

feild[4[4]] = "@"

和

feild[4] = "@"

第一个将左起所有“#”4个元素替换为“@” 第二个给出以下错误

TypeError: 'int' object is not subscriptable

Answer 1

可能您正在寻找这个 :-

size = 49
feild = []
for i in range(size):
    feild.append([])
for i in range(size):
    map(feild[i].append, ["#" for _ in xrange(size)])
i = 4
feild[i][0] = "@"

Answer 2

将 # 的第 3 行第 3 列替换为 @ 的网格：

>>> size = 5
>>> c = '#'
>>> g = [size*[c] for i in range(size)]
>>> g[3][3] = '@'
>>> print('\n'.join(' '.join(row) for row in g))
# # # # #
# # # # #
# # # # #
# # # @ #
# # # # #

用字符串替换列表元素中的列表元素

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