根据 Python 中的元素从嵌套列表中删除子列表

Question

我有以下列表：

 l = [["a", "done"], ["c", "not done"]]

如果每个子列表的第二个元素是 "done" 我想删除该子列表。所以输出应该是：

l = [["c", "not done"]]

显然下面的方法不起作用：

for i in range(len(l)):
    if l[i][1] == "done":
        l.pop(0)

Answer 1

使用list_comprehension。它只是通过迭代子列表来构建一个新列表，其中每个子列表中的第二个元素将不包含字符串 done

>>> l = [["a", "done"], ["c", "not done"]]
>>> [subl for subl in l if subl[1] != 'done']
[['c', 'not done']]
>>>

Answer 2

l = [["a", "done"], ["c", "not done"]]
print [i for i in l if i[1]!="done"]

或使用filter

l = [["a", "done"], ["c", "not done"]]
print filter(lambda x:x[1]!="done",l)

Answer 3

根据您的条件应用过滤器：

l = [["a", "done"], ["c", "not done"]]
l = filter(lambda x: len(x)>=2 and x[1]!='done', l)

Answer 4

status index is 1, you checked index 0

for i in range(len(l)):
       if(l[i][1] == "done"):
           l.pop(i)

Answer 5

使用列表理解：

l = [ item for item in l if item[-1] != 'done']

Remove a sub list from nested list based on an element in Python