如何退出 Python 中的循环?
How to exit a loop in Python?
我想让循环在 x + y =z
时停止,否则。
代码:
# -*- coding: utf-8 -*-
"""
Created on Mon Nov 16 18:39:40 2015
@author: gabri
"""
from random import randint
import os
x = randint(1,11)
y = randint(1,11)
print ("", x,"+", y,"=\n")
z = int(input("Resposta="))
if z == x + y:
input ("\n\nCorreto\nPrima enter para continuar...")
else:
for z in range(0, 10):
os.system('CLS')
input ("Incorreto.\n\n Tente de novo...")
x = randint(1,11)
y = randint(1,11)
os.system('CLS')
print ("", x,"+", y,"=\n")
z = int(input("Resposta="))
if z == x + y:
input ("\n\nCorreto\nPrima enter para continuar...")
exit
将 exit
替换为 break
。 Exit
不是在 Python.
中退出循环的方法
我想让循环在 x + y =z
时停止,否则。
代码:
# -*- coding: utf-8 -*-
"""
Created on Mon Nov 16 18:39:40 2015
@author: gabri
"""
from random import randint
import os
x = randint(1,11)
y = randint(1,11)
print ("", x,"+", y,"=\n")
z = int(input("Resposta="))
if z == x + y:
input ("\n\nCorreto\nPrima enter para continuar...")
else:
for z in range(0, 10):
os.system('CLS')
input ("Incorreto.\n\n Tente de novo...")
x = randint(1,11)
y = randint(1,11)
os.system('CLS')
print ("", x,"+", y,"=\n")
z = int(input("Resposta="))
if z == x + y:
input ("\n\nCorreto\nPrima enter para continuar...")
exit
将 exit
替换为 break
。 Exit
不是在 Python.