从缩写中获取州名

Question

我有一个应用 returns 如果单击该状态，它会显示缩写。我想在需要实际状态名称而不是缩写的应用程序中放置一条用户消息。

如果单击纽约州，我会将 "NY" 存储在名为 data.name 的变量中。我如何使用此数据根据州的缩写获取州的全名？

我正在考虑使用

var getStateInfo = function (abbrev, stateName) {

}

但我不确定要在函数中放入什么。我也知道可能有更好的方法来解决这个问题。任何帮助都会很棒。谢谢！

Answer 1

可以使用 case 语句吗？它是否检查了 data.name 和 return 适当的大小写？前任。开关(data.name) 案例 0 (data.name == "NY") return "New York"

Answer 2

您可以使用 javascript 对象作为字典：

var states = {"NY":"New York", "NJ":"New Jersey"};

并像这样访问它们：

alert(states["NY"]);

所以你的 returns 完整状态名称的函数将像这样工作：

var getStateFullName = function (stateAbbr) {
  return states[stateAbbr];
}

Answer 3

我有打字稿（可以很容易地修改为js）功能。将我们州的缩写转换为全名，反之亦然

export default function convertUsStateAbbrAndName(input: string): string | null {
  const toAbbr = input.length !== 2;

  const states = [
    ['Alabama', 'AL'],
    ['Alaska', 'AK'],
    ['American Samoa', 'AS'],
    ['Arizona', 'AZ'],
    ['Arkansas', 'AR'],
    ['Armed Forces Americas', 'AA'],
    ['Armed Forces Europe', 'AE'],
    ['Armed Forces Pacific', 'AP'],
    ['California', 'CA'],
    ['Colorado', 'CO'],
    ['Connecticut', 'CT'],
    ['Delaware', 'DE'],
    ['District Of Columbia', 'DC'],
    ['Florida', 'FL'],
    ['Georgia', 'GA'],
    ['Guam', 'GU'],
    ['Hawaii', 'HI'],
    ['Idaho', 'ID'],
    ['Illinois', 'IL'],
    ['Indiana', 'IN'],
    ['Iowa', 'IA'],
    ['Kansas', 'KS'],
    ['Kentucky', 'KY'],
    ['Louisiana', 'LA'],
    ['Maine', 'ME'],
    ['Marshall Islands', 'MH'],
    ['Maryland', 'MD'],
    ['Massachusetts', 'MA'],
    ['Michigan', 'MI'],
    ['Minnesota', 'MN'],
    ['Mississippi', 'MS'],
    ['Missouri', 'MO'],
    ['Montana', 'MT'],
    ['Nebraska', 'NE'],
    ['Nevada', 'NV'],
    ['New Hampshire', 'NH'],
    ['New Jersey', 'NJ'],
    ['New Mexico', 'NM'],
    ['New York', 'NY'],
    ['North Carolina', 'NC'],
    ['North Dakota', 'ND'],
    ['Northern Mariana Islands', 'NP'],
    ['Ohio', 'OH'],
    ['Oklahoma', 'OK'],
    ['Oregon', 'OR'],
    ['Pennsylvania', 'PA'],
    ['Puerto Rico', 'PR'],
    ['Rhode Island', 'RI'],
    ['South Carolina', 'SC'],
    ['South Dakota', 'SD'],
    ['Tennessee', 'TN'],
    ['Texas', 'TX'],
    ['US Virgin Islands', 'VI'],
    ['Utah', 'UT'],
    ['Vermont', 'VT'],
    ['Virginia', 'VA'],
    ['Washington', 'WA'],
    ['West Virginia', 'WV'],
    ['Wisconsin', 'WI'],
    ['Wyoming', 'WY'],
  ];

  // So happy that Canada and the US have distinct abbreviations
  const provinces = [
    ['Alberta', 'AB'],
    ['British Columbia', 'BC'],
    ['Manitoba', 'MB'],
    ['New Brunswick', 'NB'],
    ['Newfoundland', 'NF'],
    ['Northwest Territory', 'NT'],
    ['Nova Scotia', 'NS'],
    ['Nunavut', 'NU'],
    ['Ontario', 'ON'],
    ['Prince Edward Island', 'PE'],
    ['Quebec', 'QC'],
    ['Saskatchewan', 'SK'],
    ['Yukon', 'YT'],
  ];

  const regions = states.concat(provinces);

  let i; // Reusable loop variable

  if (toAbbr) {
    input = input.replace(/\w\S*/g, function (txt: string) {
      return txt.charAt(0).toUpperCase() + txt.substr(1).toLowerCase();
    });
    for (i = 0; i < regions.length; i++) {
      if (regions[i][0] === input) {
        return regions[i][1];
      }
    }
  } else {
    input = input.toUpperCase();
    for (i = 0; i < regions.length; i++) {
      if (regions[i][1] === input) {
        return regions[i][0];
      }
    }
  }

  return null;
}

初始来源 - github

从缩写中获取州名

Get a state name from abbreviation

javascript

arguments

function

abbreviation