尝试按 id 查找 DrawerLayout 视图时为空引用

Null ref when trying to find DrawerLayout view by id

我使用空白 Activity 作为模板创建了一个新的 Android Studio 项目。我试图让浮动应用程序按钮打开导航抽屉 Activity。

我的空白Activity:

public class RandomizerActivity extends AppCompatActivity
{
    private NavigationActivity m_Navigation;

    @Override
    protected void onCreate(Bundle savedInstanceState)
    {
        super.onCreate(savedInstanceState);

        setContentView(R.layout.activity_randomizer);
        Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
        setSupportActionBar(toolbar);

        m_Navigation = new NavigationActivity();

        FloatingActionButton fab = (FloatingActionButton) findViewById(R.id.fab);
        fab.setOnClickListener(new View.OnClickListener()
        {
            @Override
            public void onClick(View view)
            {
                m_Navigation.openDrawer();
            }
        });
    }

    ...
}

我的导航Activity:

public class NavigationActivity extends AppCompatActivity
        implements NavigationView.OnNavigationItemSelectedListener
{
    public void openDrawer()
    {
        DrawerLayout layout = (DrawerLayout) findViewById(R.id.drawer_layout);
        layout.openDrawer(GravityCompat.START);
    }

    ...

}

和 activity_navigation.xml:

<?xml version="1.0" encoding="utf-8"?>
<android.support.v4.widget.DrawerLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:app="http://schemas.android.com/apk/res-auto"
    xmlns:tools="http://schemas.android.com/tools"
    android:id="@+id/drawer_layout"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:fitsSystemWindows="true"
    tools:openDrawer="start">

    ...

</android.support.v4.widget.DrawerLayout>

当我按下 FAB 时,应用程序崩溃并出现空引用错误:

java.lang.NullPointerException: Attempt to invoke virtual method 'android.view.View android.view.Window.findViewById(int)' on a null object reference

我是 android 开发的新手,所以我想我对 Activity 实例化有根本性的误解。谁能指出我做错了什么以及正确的做法是什么?

我可能会让 RandomizerActivity 实现导航抽屉,这样您现在就可以从 FAB 的 onClick 打开它。