SQL 具有不同比较器的 IN 运算符

Question

我需要一种方法来制作一个 IN 运算符，该运算符对每个参数进行不同类型的比较，这样：

SELECT * 
FROM Table 
WHERE (par1, par2, par3) IN ((par1answer1, par2answer1, par3min1, par3max1),
                             (par1answer2, par2answer2, par3min2, par3max2),
                             ...,
                             (par1answern, par2answern, par3minn, par3maxn)

)

解释：

par1 必须等于 par1answer1 或 par1answer2
par2 必须等于 par2answer1 或 par2answer2
par3 需要介于 par3min1 和 par3max1 之间，或者 par3min2、par3max2

@EDIT
抱歉没说清楚，我不是很擅长解释，但我正在努力！
示例集：

par1    par2    par3
2       5       10
3       6       20
4       7       30
5       8       60

SELECT * 
FROM Table 
WHERE (par1, par2, par3) IN ((2,5,9,11),
                             (3,6,11,19),
                             (5,7,9,100),
                             (5,8,10,80),
                             (2,8,0,200))

Result:
par1    par2    par3
2       5       10    //matches first tuple
5       8       60    //matches fourth tuple

Answer 1

只需手写比较。 IN不会如你所愿。

where (par1 = par1answer or par1 = par1answer2)
and (par2 = par2answer1 or par2 = par2answer2)
and (par3 between par3min1 and par3max1 or par3 between par3min2 and par3max2)

Answer 2

我猜你真的想要这个：

WHERE ( (par1, par2) = (par1answer1, par2answer1) and
        par3 between par3min1 and par3max1
      ) or
      ( (par1, par2) = (par1answer2, par2answer2) and
        par3 between par3min2 and par3max2
      )

这与您的解释不完全一致，但它似乎是对您尝试查询的合理解释。

SQL 具有不同比较器的 IN 运算符

SQL IN Operator with different comparators

sql

oracle

sql-in