如何获取上周一 2-00 a.m.?

How to get the previous Monday 2-00 a.m.?

我在 Java 7.

我是 Joda-Time 的新手,想问一个简单的问题。如何获取上周一 2-00 a.m。日期?我的意思是:

____________________________________________________________________________
                              Week 1                          |   Week 2    |
______________________________________________________________|_____________|
 MONDAY       TUESDAY WENDSDAY THURSDAY FRIDAY SATURDAY SUNDAY|  MONDAY ... |
2-00 a.m.                                                     | 2-00 a.m.   |
______________________________________________________________|_____________|

所以,我需要 return Week 1 的星期一 2-00 a.m。 iff​​ 当前时间介于 Week 1 的周一 2-00 a.m 之间。和 Week 2 的星期一 2-00 a.m.

是否有通过 Joda-Time 实现的相对简单的方法?

首先,Joda-Time 中的一个解决方案。二、新的java.time framework built into Java 8 and later, intended as the successor to Joda-Time. See Tutorial.

中的类似解决方案

以下两种解决方案都遵循类似的逻辑,综合总结如下。 Joda DateTime and Java8 LocalDateTime provide immutable datetime implementations using the fluent interface。要到达上周星期一凌晨 2 点,您可以执行以下步骤,使用流畅的界面链接后续调用:

  1. 使用 LocalDateTime.minus 方法减去星期几与星期一之间的差值,得到过去星期一的当前时间
  2. 减去今天的毫秒数以得到过去的星期一00:00am
  3. 使用 LocalDateTime.plus 方法增加 2 小时。

乔达时间

    DateTime currentTime = new DateTime();
    DateTime dateResult;
    boolean shouldReturnLastMonday = (currentTime.getDayOfWeek() != DateTimeConstants.MONDAY ||
            currentTime.hourOfDay().get() < 2);
    if (shouldReturnLastMonday) {
        dateResult = currentTime.minus(Days.days(currentTime.getDayOfWeek() - DateTimeConstants.MONDAY))
                .minus(currentTime.getMillisOfDay())
                .plus(Hours.hours(2));
    } else {
        dateResult = currentTime.minus(currentTime.getMillisOfDay())
                .plus(Hours.hours(2));
    }
    System.out.println(dateResult);

java.time

  LocalDateTime currentTime = LocalDateTime.now();
  LocalDateTime dateResult;
  boolean shouldReturnLastMonday = (currentTime.getDayOfWeek() != DayOfWeek.MONDAY) ||
                                    (currentTime.getDayOfWeek() != DayOfWeek.MONDAY && currentTime.getHour() < 2);
  if(shouldReturnLastMonday) {
      dateResult = currentTime.minus(currentTime.getDayOfWeek().getValue() - DayOfWeek.MONDAY.getValue(), ChronoUnit.DAYS)
              .minus(currentTime.getLong(ChronoField.MILLI_OF_DAY), ChronoUnit.MILLIS)
              .plus(2, ChronoUnit.HOURS);
  } else {
      dateResult = currentTime.minus(currentTime.getLong(ChronoField.MILLI_OF_DAY), ChronoUnit.MILLIS)
              .plus(2,ChronoUnit.HOURS);
  }