为记忆匹配游戏洗牌 2 天数组

Question

您好，我正在尝试创建一个记忆配对游戏。我能够随机化数组状态以获得不同的值，但是在我将 states 数组的 8 个元素中的 2x 加载到名为 tempGrid[][] 的数组中之后，我似乎无法对内容进行混音。例如，我得到的结果是：

AL AK AZ AR 
AL AK AZ AR 
CA CO CT DE
CA CO CT DE

但我正在尝试

AK AL CA CT
CT DE CA AK
DE AL AR AR
CO AZ AZ CO

我怎样才能做到这一点？谢谢你的帮助。下面的代码

import java.util.*;
public class createGrid
{

    private static String[][] tempGrid ={{"00", "01", "02", "03"},
                                      {"10", "11", "12", "13"},
                                      {"20", "21", "22", "23"},
                                      {"30", "31", "32", "33"},
                                     };

    static String[] states = {"AL", "AK", "AZ", "AR", "CA", "CO", "CT", "DE",
                              "FL", "GA", "HI", "ID", "IL", "IN", "IA", "KS", 
                              "KY", "LA", "ME", "MD", "MA", "MI", "MN", "MS",
                              "MO", "MT", "NE", "NV", "NH", "NJ", "NM", "NY", 
                              "NC", "ND", "OH", "OK", "OR", "PA", "RI", "SC",
                              "SD", "TN", "TX", "UT", "VT", "VA", "WA", "WV",
                              "WI", "WY"};
     static String[][] themeGrid = new String[4][4];
    public static void setThemeGrid()
    {   
        //filles temp grid with 8 elements x2
        for (int counter = 0; counter < 4; counter++)
        {
            themeGrid[0][counter] = states[counter];
            themeGrid[0][counter] = states[counter];
            themeGrid[0][counter] = states[counter];
            themeGrid[0][counter] = states[counter];

            themeGrid[1][counter] = states[counter];
            themeGrid[1][counter] = states[counter];
            themeGrid[1][counter] = states[counter];
            themeGrid[1][counter] = states[counter];

            themeGrid[2][counter] = states[counter+4];
            themeGrid[2][counter] = states[counter+4];
            themeGrid[2][counter] = states[counter+4];
            themeGrid[2][counter] = states[counter+4];

            themeGrid[3][counter] = states[counter+4];
            themeGrid[3][counter] = states[counter+4];
            themeGrid[3][counter] = states[counter+4];
            themeGrid[3][counter] = states[counter+4];
        }
         //Collections.shuffle(Arrays.asList(themeGrid);
         //doessn't seem to work

        System.out.println("This is the randomized theme grid");
        for (int row = 0; row < 4; row++)
        {
            for (int column = 0; column < 4; column++)
            { 
                System.out.printf("%s ", themeGrid[row][column]);


            }System.out.println();
        }
    }



    public static void main(String[] args)
    {
        setThemeGrid();

    }     
}

Answer 1

随机化列表或数组的最简单方法是创建一个 returns 随机值的比较器，如下所示：

public class RandomComparator<T> implements Comparator<T>{
    private Random rand = new Random();

    @Override
    public int compare(T a, T b) {
        return rand.nextInt(2) - 1;
    }   
}

您可以将 RandomComparator 与 Arrays.sort() 或 Collections.sort() 一起使用，以随机化任何数组或集合的顺序。

对于像您这样的多向量数组，您需要分别打乱每个 'row'，然后打乱 'columns'。也许多次才能让它们变好并混合。

Answer 2

我不清楚为什么要将 themeGrid 的每个元素设置四次。但我相信这会如您所愿。

public static void setThemeGrid()
{   
    //fills temp grid with 8 elements x2
    List themeList = new ArrayList()
    for (int counter = 0; counter < 4; counter++)
    {
        themeList.add(states[counter]);
        themeList.add(states[counter]);
        themeList.add(states[counter+4]);
        themeList.add(states[counter+4]);
    }
    Collections.shuffle(themeList);

    System.out.println("This is the randomized theme grid");
    for (int row = 0; row < 4; row++)
    {
        for (int column = 0; column < 4; column++)
        {
            themeGrid[row][column] = themeList.get(row*4 + column);
            System.out.printf("%s ", themeGrid[row][column]);
        }
        System.out.println();
    }
}

如果您希望能够轻松地重新排列同一个网格，只需将 themeList 保存为静态变量，而不是 themeGrid 或者除了 themeGrid 之外。

为记忆匹配游戏洗牌 2 天数组

Shuffling 2-Day array for memory match game

java

arrays

match

shuffle