将 timeFrom 和 timeTo 分成小时间隔

Question

我有以下内容：

TimeFrom                    TimeTo
2015-08-04 11:00:00.000     2015-08-04 14:00:00.000
2015-08-04 18:00:00.000     2015-08-04 20:00:00.000
2015-08-04 21:00:00.000     2015-08-04 23:00:00.000

我想创建一个能给我所有小时间隔的东西。像这样：

TimeFrom                    TimeTo
2015-08-04 11:00:00.000     2015-08-04 12:00:00.000
2015-08-04 12:00:00.000     2015-08-04 13:00:00.000
2015-08-04 13:00:00.000     2015-08-04 14:00:00.000
2015-08-04 18:00:00.000     2015-08-04 19:00:00.000
2015-08-04 19:00:00.000     2015-08-04 20:00:00.000
2015-08-04 21:00:00.000     2015-08-04 22:00:00.000
2015-08-04 22:00:00.000     2015-08-04 23:00:00.000

有没有简单的方法可以做到这一点？看起来应该很常见，但找不到与此相关的任何内容。

我记录了很多天，快一年了。所有个人记录（timeFrom、timeTo）都在同一天（它们不会跨越多天）。

我正在使用 PrestoDB

Answer 1

如果没有另一个每小时列出的 table，我看不到实现的方法。如果你被限制在一天之内，你可以通过使用 UNION ALL

在你的查询中构造它来伪造它

SELECT h.Hour
  FROM ( SELECT 2015-08-04 00:00:00.000 AS Hour
         UNION ALL SELECT 2015-08-04 01:00:00.000    
         UNION ALL SELECT 2015-08-04 02:00:00.000  
         UNION ALL SELECT 2015-08-04 03:00:00.000  
         UNION ALL SELECT 2015-08-04 04:00:00.000  
         UNION ALL SELECT 2015-08-04 05:00:00.000  
         UNION ALL SELECT 2015-08-04 06:00:00.000  
         UNION ALL SELECT 2015-08-04 07:00:00.000  
         UNION ALL SELECT 2015-08-04 08:00:00.000  
         UNION ALL SELECT 2015-08-04 09:00:00.000  
         UNION ALL SELECT 2015-08-04 10:00:00.000  
         UNION ALL SELECT 2015-08-04 11:00:00.000 
         UNION ALL SELECT 2015-08-04 12:00:00.000 
         UNION ALL SELECT 2015-08-04 13:00:00.000 
         UNION ALL SELECT 2015-08-04 14:00:00.000 
         UNION ALL SELECT 2015-08-04 15:00:00.000 
         UNION ALL SELECT 2015-08-04 16:00:00.000 
         UNION ALL SELECT 2015-08-04 17:00:00.000 
         UNION ALL SELECT 2015-08-04 18:00:00.000 
         UNION ALL SELECT 2015-08-04 19:00:00.000 
         UNION ALL SELECT 2015-08-04 20:00:00.000 
         UNION ALL SELECT 2015-08-04 21:00:00.000 
         UNION ALL SELECT 2015-08-04 22:00:00.000 
         UNION ALL SELECT 2015-08-04 23:00:00.000 ) AS h
where exists 
(select id from mytable where h>=TimeFrom and h<=TimeTo)

Answer 2

您可以使用数字 table:

SELECT DATE_ADD('HOUR', i - 1, TimeFrom) AS TimeFrom, 
       DATE_ADD('HOUR', i, TimeFrom) AS TimeTo
FROM (SELECT 1 AS i UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4
      UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8
      UNION ALL SELECT 9 UNION ALL SELECT 10 UNION ALL SELECT 11 UNION ALL SELECT 12
      UNION ALL SELECT 13 UNION ALL SELECT 14 UNION ALL SELECT 15 UNION ALL SELECT 16
      UNION ALL SELECT 17 UNION ALL SELECT 18 UNION ALL SELECT 19 UNION ALL SELECT 20
      UNION ALL SELECT 21 UNION ALL SELECT 22 UNION ALL SELECT 23 UNION ALL SELECT 24
) AS numbers
INNER JOIN mytable ON numbers.i <= DATE_DIFF('HOUR', TimeFrom, TimeTo)
ORDER BY TimeFrom

注意： 上述查询使用 DATE_ADD 和 DATE_DIFF 日期和时间函数 here for PrestoDB。

将 timeFrom 和 timeTo 分成小时间隔

splitting up timeFrom and timeTo into hour intervals

mysql

sql

presto