将矩阵乘以用户输入

Multiply matrix by user input

这是一个将矩阵乘以多个用户输入的代码示例。该动作应重复用户输入的次数。例如,如果我输入数字 3,我会得到 3 个相同的打印矩阵。相反,我希望该矩阵乘以数字 3 3 次(每个新矩阵乘以数字 3)。有谁知道我该怎么做?谢谢

*using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace user_input
{
    class Program
    {
        static void Main(string[] args)
        {
            string[] nodes = { "1", "2", "3", "4", "5", "6" };
            int[,] adjmatrix = new int[,]
                    {{2,7,3,8,4},
                     {7,0,8,2,6},
                     {6,8,4,9,7},
                     {8,5,9,8,8},
                     {4,9,7,8,1}
                    };
            int[,] newmatrix = new int[adjmatrix.GetLength(0), adjmatrix.GetLength(1)];
            Printmatrix(adjmatrix, nodes, nodes, "Input Matrix");
            Newline();
            int n = 0;
            System.Console.WriteLine("Please enter a number");
            n = Convert.ToInt32(Console.ReadLine());
            for (int i = 0; i < n; i++)
            {
                MultipliedMatrix(ref newmatrix, adjmatrix, n);
                Newline();
                Printmatrix(newmatrix, nodes, nodes, "Multiplied Matrix");
            }


            Console.ReadKey();
        }
        private static void Newline()
        {
            Console.Write("\n");
        }
        private static void MultipliedMatrix(ref int[,] newmatrix, int[,] adjmatrix, int n)
        {
            for (int i = 0; i < adjmatrix.GetLength(0); i++)
            {
                for (int j = 0; j < adjmatrix.GetLength(1); j++)
                {
                    newmatrix[i, j] = adjmatrix[i, j] * n;
                }
            }
        }

        private static void Printmatrix(int[,] adjmatrix, string[] nodes_h, string[] nodes_v, string title)
        {
            if (adjmatrix.GetLength(0) != 0)
            {
                Console.ForegroundColor = ConsoleColor.White;
                Console.Write("{0}\n", title);
                Console.ForegroundColor = ConsoleColor.DarkGreen;
                Console.Write("\t");
                for (int i = 0; i < adjmatrix.GetLength(0); i++)
                    Console.Write("{0}\t", nodes_v[i]);
                for (int i = 0; i < adjmatrix.GetLength(0); i++)
                {
                    Newline();
                    Console.ForegroundColor = ConsoleColor.DarkGreen;
                    Console.Write("{0}\t", nodes_h[i]);
                    for (int j = 0; j < adjmatrix.GetLength(1); j++)
                    {
                        Console.ForegroundColor = ConsoleColor.DarkGray;
                        if (adjmatrix[i, j] < 500) Console.Write("{0}\t", adjmatrix[i, j]);
                        else
                        {
                            Console.ForegroundColor = ConsoleColor.Red;
                            Console.Write("-\t", adjmatrix[i, j]);
                        }
                    }
                    Console.ForegroundColor = ConsoleColor.White;
                }
                Newline();
            }
        }
    }
}*

*

您一直将相同的矩阵作为输入传递给 MultipliedMatrix(),所以它一直在做同样的事情。

要使其对新矩阵进行操作,请在循环内调用 Printmatrix() 后立即添加以下行:

adjmatrix = newmatrix;

或者(更好的 IMO)是将 MultipliedMatrix() 更改为 return 新矩阵,如下所示:

private static int[,] MultipliedMatrix(int[,] adjmatrix, int n)
{
    int[,] newmatrix = new int[adjmatrix.GetLength(0), adjmatrix.GetLength(1)];

    for (int i = 0; i < adjmatrix.GetLength(0); i++)
        for (int j = 0; j < adjmatrix.GetLength(1); j++)
            newmatrix[i, j] = adjmatrix[i, j] * n;

    return newmatrix;
}

那么乘法循环中的代码将如下所示:

    for (int i = 0; i < n; i++)
    {
        adjmatrix = MultipliedMatrix(adjmatrix, n);
        Newline();
        Printmatrix(adjmatrix, nodes, nodes, "Multiplied Matrix");
    }

请注意,这会丢失对原始 adjmatrix 的引用,这对您当前的代码来说不是问题。

但是,如果您需要保留原始参考,请这样做:

var newMatrix = adjmatrix;

for (int i = 0; i < n; i++)
{
    newMatrix = MultipliedMatrix(newMatrix, n);
    Newline();
    Printmatrix(adjmatrix, nodes, nodes, "Multiplied Matrix");
}

首先我会将乘法更改为函数而不是 void 方法调用,因此它看起来比 then

这将是伪代码:

n = userinput;
i=0;
int[,] result;

do
  i+=1;
  result = MultiplyMatrix(result, n);
while i<n


int[,] MultiplyMatrix(adjmatrix, n){
   (multiply)  
   return resultMatrix };