将 SPARQL 结果解析为 jtable

Question

我正在处理 Apache Jena 项目。我的本地主机上有一个 Fuseki 服务器运行。我想为我的 Fuseki 服务器创建一个 Java 程序，它在 JTable 中显示三元组中的所有数据。我只是不知道如何将查询结果解析为 JTable。

到目前为止我的代码：（省略了创建 window、table、框架等的部分）

private void Go() {
    String query = "SELECT ?subject ?predicate ?object \n" +
                   "WHERE { \n" +
                   "?subject ?predicate ?object }";
    Query sparqlQuery = QueryFactory.create(query, Syntax.syntaxARQ) ;
    QueryEngineHTTP httpQuery = new QueryEngineHTTP("http://localhost:3030/AnimalDataSet/", sparqlQuery);

    ResultSet results = httpQuery.execSelect();
    System.out.println(ResultSetFormatter.asText(results));
    while (results.hasNext()) {
        QuerySolution solution = results.next();
    }
    httpQuery.close();
}

sysout 打印了这个，这是正确的数据：

-------------------------------------------------------------------------------------------------------------------------------------
| subject                    | predicate                                         | object                                           |
=====================================================================================================================================
| <urn:animals:data>         | <http://www.w3.org/1999/02/22-rdf-syntax-ns#type> | <http://www.w3.org/1999/02/22-rdf-syntax-ns#Seq> |
| <urn:animals:data>         | <http://www.w3.org/1999/02/22-rdf-syntax-ns#_1>   | <urn:animals:lion>                               |
| <urn:animals:data>         | <http://www.w3.org/1999/02/22-rdf-syntax-ns#_2>   | <urn:animals:tarantula>                          |
| <urn:animals:data>         | <http://www.w3.org/1999/02/22-rdf-syntax-ns#_3>   | <urn:animals:hippopotamus>                       |
| <urn:animals:lion>         | <http://www.some-ficticious-zoo.com/rdf#name>     | "Lion"                                           |
| <urn:animals:lion>         | <http://www.some-ficticious-zoo.com/rdf#species>  | "Panthera leo"                                   |
| <urn:animals:lion>         | <http://www.some-ficticious-zoo.com/rdf#class>    | "Mammal"                                         |
| <urn:animals:tarantula>    | <http://www.some-ficticious-zoo.com/rdf#name>     | "Tarantula"                                      |
| <urn:animals:tarantula>    | <http://www.some-ficticious-zoo.com/rdf#species>  | "Avicularia avicularia"                          |
| <urn:animals:tarantula>    | <http://www.some-ficticious-zoo.com/rdf#class>    | "Arachnid"                                       |
| <urn:animals:hippopotamus> | <http://www.some-ficticious-zoo.com/rdf#name>     | "Hippopotamus"                                   |
| <urn:animals:hippopotamus> | <http://www.some-ficticious-zoo.com/rdf#species>  | "Hippopotamus amphibius"                         |
| <urn:animals:hippopotamus> | <http://www.some-ficticious-zoo.com/rdf#class>    | "Mammal"                                         |
-------------------------------------------------------------------------------------------------------------------------------------

我真的希望这里有人知道如何将查询中的数据解析为 JTbale :D

提前致谢！

Answer 1

我做了一些进一步的研究，终于找到了解决方案！其实很简单。

您只需像这样简单地更改 while 循环：

while(rs.hasNext())
    {
        QuerySolution sol = rs.nextSolution();
        RDFNode object = sol.get("object"); 
        RDFNode predicate = sol.get("predicate"); 
        RDFNode subject = sol.get("subject");

        DefaultTableModel model = (DefaultTableModel) table.getModel();
        model.addRow(new Object[]{subject, predicate, object});
    }

这对我来说很好用！

对于所有感兴趣的人，我已经将我的版本发布到 pastebin，其中有评论： The link to the full (current) version of my project

将 SPARQL 结果解析为 jtable

Parsing SPARQL Result into jtable

java

rdf

apache-jena