MySQL CodeIgniter 中的等效查询

Question

MySQL查询如下

select PB.*, P.*, WhoCreated.*, WhoPlacedBid.* from tblprojectbid PB
Inner Join tblproject P on P.projectid = PB.projectid
Inner Join tbluser WhoCreated WhoCreated.UserID = P.WhoCreated
Inner Join tbluser WhoPlacedBid WhoPlacedBid.UserID = PB.WhoCreated
Where PB.FreelancerAwardedProjectStatusID in (4, 5)
and WhoCreated.UserID = 3
and PB.Reviewgiven = 0

下面是用CodeIgnitor写的查询。

$this->_ci->db->select('PB.*, P.*, WhoCreated.*, WhoPlacedBid.*');
$this->_ci->db->from('tblprojectbid PB');
$this->_ci->db->join('tblproject P', 'P.projectid = PB.projectid');
$this->_ci->db->join('tbluser WhoCreated', 'WhoCreated.UserID = P.WhoCreated');
$this->_ci->db->join('tbluser WhoPlacedBid', 'WhoPlacedBid.UserID = PB.WhoCreated');
$this->_ci->db->or_where('PB.FreelancerAwardedProjectStatusID', 4);
$this->_ci->db->or_where('PB.FreelancerAwardedProjectStatusID', 5);
$this->_ci->db->where('WhoCreated.UserID', 5);
$this->_ci->db->where('PB.Reviewgiven', 5);
$query = $this->_ci->db->get();

能否请您帮助更正上述查询，使其等同于上述 MYSQL 查询？

Answer 1

小更正：

1) 将第二个参数 false 添加到 select() 以避免反引号。
2) 使用 where_in

$this->_ci->db->select('PB.*, P.*, WhoCreated.*, WhoPlacedBid.*',false);
$this->_ci->db->from('tblprojectbid PB');
$this->_ci->db->join('tblproject P', 'P.projectid = PB.projectid');
$this->_ci->db->join('tbluser WhoCreated', 'WhoCreated.UserID = P.WhoCreated');
$this->_ci->db->join('tbluser WhoPlacedBid', 'WhoPlacedBid.UserID = PB.WhoCreated');
$this->_ci->db->where_in('PB.FreelancerAwardedProjectStatusID', array(4,5));
$this->_ci->db->where('WhoCreated.UserID', 5);
$this->_ci->db->where('PB.Reviewgiven', 5);
$query = $this->_ci->db->get();

让我知道它是否有效。

Answer 2

$this->db->select() 接受可选的第二个参数。如果您将其设置为 FALSE，CodeIgniter 将不会尝试使用反引号保护您的字段或 table 名称。您不需要重复 $this->_ci->db-> 直到您不想使用条件语句添加连接或条件。使用 where_in() 来检查具有多个值的相同列名。您可以像这样优化代码：

$this->_ci->db->select('PB.*, P.*, WhoCreated.*, WhoPlacedBid.*',FALSE)
            ->from('tblprojectbid PB')
            ->join('tblproject P', 'P.projectid = PB.projectid')
            ->join('tbluser WhoCreated', 'WhoCreated.UserID = P.WhoCreated')
            ->join('tbluser WhoPlacedBid', 'WhoPlacedBid.UserID = PB.WhoCreated')
            ->where_in('PB.FreelancerAwardedProjectStatusID', array(4,5))
            ->where(array('WhoCreated.UserID'   =>  5, 'PB.Reviewgiven' =>  5))        
            ->get();

MySQL CodeIgniter 中的等效查询

MySQL Query equivalent in CodeIgniter

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