我的网络抓取工具代码有什么问题 (python3.4)

Question

我正在尝试从网站上抓取 table。它运行但我没有得到我的文件的输出。我哪里错了？

代码：

from bs4 import BeautifulSoup

import urllib.request

f = open('nbapro.txt','w')
errorFile = open('nbaerror.txt','w')

page = urllib.request.urlopen('http://www.numberfire.com/nba/fantasy/full-fantasy-basketball-projections')

content = page.read()
soup =  BeautifulSoup(content)

tableStats = soup.find('table', {'class': 'data-table xsmall'})
for row in tableStats.findAll('tr')[2:]:
 col = row.findAll('td')

 try: 
    name = col[0].a.string.strip()
    f.write(name+'\n')
 except Exception as e:
    errorFile.write (str(e) + '******'+ str(col) + '\n')
    pass

f.close
errorFile.close

Answer 1

问题是您尝试抓取的 table 数据是通过在浏览器端调用 javascript 代码来填充的。 urllib 不是浏览器，因此无法执行 javascript.

如果你想通过urllib和BeautifulSoup解决它，你必须从script标签中提取JSON对象并通过[=15加载它=].例如，打印玩家姓名：

import json
import re
import urllib.request
from bs4 import BeautifulSoup


soup = BeautifulSoup(urllib.request.urlopen('http://www.numberfire.com/nba/fantasy/full-fantasy-basketball-projections'))

script = soup.find('script', text=lambda x: x and 'NF_DATA' in x).text
data = re.search(r'NF_DATA = (.*?);', script).group(1)
data = json.loads(data)

for player_id, player in data['players'].items():
    print(player['name'] + ' ' + player['last_name'])

我的网络抓取工具代码有什么问题 (python3.4)

What is wrong with my web scraper code (python3.4)

python

beautifulsoup

html-parsing

web-scraping

python-3.x