如何输出包含结构位置的集合

Question

这是基本 A* 算法的开始，如何输出集合中的内容？到目前为止我所拥有的不起作用，我收到此错误

"Error 1 error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'const Location' (or there is no acceptable conversion)"

void astar(Location Start_Location, Location End_Location)
{
    Location Current_Location;
    Current_Location.g = 1;
    Start_Location.g = 1;

    int position = 0;
    bool found = false;

    Start_Location.g = 0;
    Start_Location.h = (abs(Start.x - End.x) + abs(Start.y - End.y));
    Start_Location.f = Start_Location.g + Start_Location.h;

    std::set<Location> myset;
    std::set<Location>::iterator it;

    myset.insert(it, Start_Location);

    current_Coord.x = End.x;
    current_Coord.y = End.y;

    /*while (!myset.empty())
    {*/
        Current_Location.h = (abs(current_Coord.x - End.x) + abs(current_Coord.y - End.y));
        Current_Location.f = Current_Location.g + Current_Location.h;

        //calculates f around current node
            Current_Location.h = (abs(current_Coord.x - End.x) + abs((current_Coord.y - 1) - End.y));
            Current_Location.f = Current_Location.g + Current_Location.h;
            myset.insert(it, Current_Location);

            Current_Location.h = (abs(current_Coord.x - End.x) + abs((current_Coord.y + 1) - End.y));
            Current_Location.f = Current_Location.g + Current_Location.h;
            myset.insert(it, Current_Location);

            Current_Location.h = (abs((current_Coord.x - 1) - End.x) + abs(current_Coord.y - End.y));
            Current_Location.f = Current_Location.g + Current_Location.h;
            myset.insert(it, Current_Location);

            Current_Location.h = (abs((current_Coord.x + 1) - End.x) + abs(current_Coord.y - End.y));
            Current_Location.f = Current_Location.g + Current_Location.h;
            myset.insert(it, Current_Location);


            for (it = myset.begin(); it != myset.end(); ++it)
            {
                cout << ' ' << *it;
            }

    //}
}

Answer 1

"Error 1 error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'const Location' (or there is no acceptable conversion)"

如果您仔细阅读错误，您会发现您正试图将类型为 'const Location' 的对象作为参数传递给您在 for 循环中执行的提取运算符。

for (it = myset.begin(); it != myset.end(); ++it)
{
    cout << ' ' << *it;
}

问题是编译器找不到任何接受该类型的重载（或可接受的转换）。这意味着你肯定没有定义它。

解决方案。

解决方案很简单，您必须为 << 运算符定义适当的重载。以下示例是您可以执行此操作的多种方法之一。

struct Location
{
    int f, g, h;

    friend std::ostream& operator<<(std::ostream& os, const Location& l)
    {
        os << l.f << ' ' << l.g << ' ' << l.h;
        return os;
    }
};

如何输出包含结构位置的集合

How to output a set containing a Struct Location for

c++

a-star

set

output