如何使用 php 和 header 在两列中显示数据
how to display data in two column with php with header
我有数据库
---------------------------------------------
no | name | code | grade
---------------------------------------------
1 | john | A1 | C
2 | john | A2 | D
3 | john | A3 | B
4 | tom | A1 | A
5 | john | A4 | A
6 | alice | A1 | C
7 | alice | A2 | D
8 | john | A5 | D
9 | john | A6 | C
---------------------------------------------
当我想要显示名为 john 的数据时,我想要包含 2 列的结果:
---------------------------------------------------------------
no | name | code | grade | no | name | code | grade |
---------------------------------------------------------------
1 | john | A1 | C | 5 | john | A5 | D |
2 | john | A2 | D | 6 | john | A6 | C |
3 | john | A3 | B | | | | |
4 | john | A4 | A | | | | |
---------------------------------------------------------------
这是我已经尝试过的代码
$result = mysql_query("select * from grade ");
echo "<table border='1'><tr>";
echo "<td>no</td>";
echo "<td>name</td>";
echo "<td>code</td>";
echo "<td>grade</td></tr><tr>";
$no = 1;
$count = 1;
while ($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
extract($row);
echo "<td>$no</td>";
echo "<td>$row[name]</td>";
echo "<td>$row[code]</td>";
echo "<td>$row[grade]</td>";
if ($count++ % 2 == 0)
{
echo "</tr><tr>";
$no++;
}
}
echo "</tr></table>";
但是结果不是我想要的,这是我运行我的代码
时的结果
no | name | code | grade | | | | |
---------------------------------------------------------------
1 | john | A1 | C | 1 | john | A4 | A |
2 | john | A2 | D | 2 | john | A5 | D |
3 | john | A3 | B | 3 | john | A6 | C |
---------------------------------------------------------------
有人可以帮助我吗...谢谢
我没有对此进行测试,也没有检查错误,但我认为它符合您要完成的目标。
$result = mysql_query("select * from grade ");
$orig_count = mysql_num_rows($result);
if ( $orig_count % 2 != 0 )
$count = $orig_count + 1;
$cols = $count / 2;
//draw header
echo "<table border='1'><tr>";
echo "<td>no</td>";
echo "<td>name</td>";
echo "<td>code</td>";
echo "<td>grade</td></tr><tr>"
for ( $i = 0; $i < $cols; i++ )
{
if ( $orig_count == 0 )
break; //zero results
//first column
echo "<td>$i</td>";
echo "<td>".mysql_result( $result, $i, "name" )."</td>";
echo "<td>".mysql_result( $result, $i, "code" )."</td>";
echo "<td>".mysql_result( $result, $i, "grade" )."</td>";
//second column
if ( $i > $orig_count )
{
echo "<td> </td>";
echo "<td> </td>";
echo "<td> </td>";
echo "<td> </td>";
}
else
{
echo "<td>".$i+($count/2)."</td>";
echo "<td>".mysql_result( $result, $i+($count/2), "name" )."</td>";
echo "<td>".mysql_result( $result, $i+($count/2), "code" )."</td>";
echo "<td>".mysql_result( $result, $i+($count/2), "grade" )."</td>";
}
}
//finish off
echo "</tr></table>";
这是表示问题,所以可以通过两种方式解决。
1. 您可以使用 modern HTML:
创建此列
<section style="-webkit-column-count:2; -webkit-column-gap:15;">
<div class='columns'>
<table>
<tr>
<th>no</th>
<th>name</th>
<th>code</th>
<th>grade</th>
</tr>
<?php
$result = mysql_query("select * from grade ");
$no = 1;
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo '<tr>';
echo "<td>{$row['no']}</td>";
echo "<td>{$row['name']}</td>";
echo "<td>{$row['code']}</td>";
echo "<td>{$row['grade']}</td>";
echo '</tr>';
$no++;
}
?>
</table>
</div>
</section>
2.如果你想坚持使用普通表格,你必须做一些计算:
首先,您需要知道要显示的全部成绩。您可以使用 SQL 查询(更有效的方式)来获取它,我将通过将所有数据预加载到数组来实现。 HTML 为简洁起见,省略了页脚和页眉。
<?php
$data = array();
$result = mysql_query('SELECT * FROM grade;');
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
$data[] = $row;
}
$rows = (int) ceil(count($data)/2);
for ($i=0; $i < $rows; $i++) {
$no = $i + 1;
echo '<tr>';
echo "<td>{$no}</td>";
echo "<td>{$data[$i]['name']}</td>";
echo "<td>{$data[$i]['code']}</td>";
echo "<td>{$data[$i]['grade']}</td>";
if (array_key_exists($i + $rows, $data)) {
$no = $i + $rows + 1;
echo "<td>{$no}</td>";
echo "<td>{$data[$i + $rows]['name']}</td>";
echo "<td>{$data[$i + $rows]['code']}</td>";
echo "<td>{$data[$i + $rows]['grade']}</td>";
} else {
echo "<td> </td>";
echo "<td> </td>";
echo "<td> </td>";
echo "<td> </td>";
}
echo "</tr>\n";
}
我有数据库
---------------------------------------------
no | name | code | grade
---------------------------------------------
1 | john | A1 | C
2 | john | A2 | D
3 | john | A3 | B
4 | tom | A1 | A
5 | john | A4 | A
6 | alice | A1 | C
7 | alice | A2 | D
8 | john | A5 | D
9 | john | A6 | C
---------------------------------------------
当我想要显示名为 john 的数据时,我想要包含 2 列的结果:
---------------------------------------------------------------
no | name | code | grade | no | name | code | grade |
---------------------------------------------------------------
1 | john | A1 | C | 5 | john | A5 | D |
2 | john | A2 | D | 6 | john | A6 | C |
3 | john | A3 | B | | | | |
4 | john | A4 | A | | | | |
---------------------------------------------------------------
这是我已经尝试过的代码
$result = mysql_query("select * from grade ");
echo "<table border='1'><tr>";
echo "<td>no</td>";
echo "<td>name</td>";
echo "<td>code</td>";
echo "<td>grade</td></tr><tr>";
$no = 1;
$count = 1;
while ($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
extract($row);
echo "<td>$no</td>";
echo "<td>$row[name]</td>";
echo "<td>$row[code]</td>";
echo "<td>$row[grade]</td>";
if ($count++ % 2 == 0)
{
echo "</tr><tr>";
$no++;
}
}
echo "</tr></table>";
但是结果不是我想要的,这是我运行我的代码
时的结果no | name | code | grade | | | | |
---------------------------------------------------------------
1 | john | A1 | C | 1 | john | A4 | A |
2 | john | A2 | D | 2 | john | A5 | D |
3 | john | A3 | B | 3 | john | A6 | C |
---------------------------------------------------------------
有人可以帮助我吗...谢谢
我没有对此进行测试,也没有检查错误,但我认为它符合您要完成的目标。
$result = mysql_query("select * from grade ");
$orig_count = mysql_num_rows($result);
if ( $orig_count % 2 != 0 )
$count = $orig_count + 1;
$cols = $count / 2;
//draw header
echo "<table border='1'><tr>";
echo "<td>no</td>";
echo "<td>name</td>";
echo "<td>code</td>";
echo "<td>grade</td></tr><tr>"
for ( $i = 0; $i < $cols; i++ )
{
if ( $orig_count == 0 )
break; //zero results
//first column
echo "<td>$i</td>";
echo "<td>".mysql_result( $result, $i, "name" )."</td>";
echo "<td>".mysql_result( $result, $i, "code" )."</td>";
echo "<td>".mysql_result( $result, $i, "grade" )."</td>";
//second column
if ( $i > $orig_count )
{
echo "<td> </td>";
echo "<td> </td>";
echo "<td> </td>";
echo "<td> </td>";
}
else
{
echo "<td>".$i+($count/2)."</td>";
echo "<td>".mysql_result( $result, $i+($count/2), "name" )."</td>";
echo "<td>".mysql_result( $result, $i+($count/2), "code" )."</td>";
echo "<td>".mysql_result( $result, $i+($count/2), "grade" )."</td>";
}
}
//finish off
echo "</tr></table>";
这是表示问题,所以可以通过两种方式解决。
1. 您可以使用 modern HTML:
<section style="-webkit-column-count:2; -webkit-column-gap:15;">
<div class='columns'>
<table>
<tr>
<th>no</th>
<th>name</th>
<th>code</th>
<th>grade</th>
</tr>
<?php
$result = mysql_query("select * from grade ");
$no = 1;
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo '<tr>';
echo "<td>{$row['no']}</td>";
echo "<td>{$row['name']}</td>";
echo "<td>{$row['code']}</td>";
echo "<td>{$row['grade']}</td>";
echo '</tr>';
$no++;
}
?>
</table>
</div>
</section>
2.如果你想坚持使用普通表格,你必须做一些计算: 首先,您需要知道要显示的全部成绩。您可以使用 SQL 查询(更有效的方式)来获取它,我将通过将所有数据预加载到数组来实现。 HTML 为简洁起见,省略了页脚和页眉。
<?php
$data = array();
$result = mysql_query('SELECT * FROM grade;');
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
$data[] = $row;
}
$rows = (int) ceil(count($data)/2);
for ($i=0; $i < $rows; $i++) {
$no = $i + 1;
echo '<tr>';
echo "<td>{$no}</td>";
echo "<td>{$data[$i]['name']}</td>";
echo "<td>{$data[$i]['code']}</td>";
echo "<td>{$data[$i]['grade']}</td>";
if (array_key_exists($i + $rows, $data)) {
$no = $i + $rows + 1;
echo "<td>{$no}</td>";
echo "<td>{$data[$i + $rows]['name']}</td>";
echo "<td>{$data[$i + $rows]['code']}</td>";
echo "<td>{$data[$i + $rows]['grade']}</td>";
} else {
echo "<td> </td>";
echo "<td> </td>";
echo "<td> </td>";
echo "<td> </td>";
}
echo "</tr>\n";
}