遍历 python 中命名元组的元素

Question

我有一个命名元组，我像这样为其赋值：

class test(object):
            self.CFTs = collections.namedtuple('CFTs', 'c4annual c4perren c3perren ntfixing')

            self.CFTs.c4annual = numpy.zeros(shape=(self.yshape, self.xshape))
            self.CFTs.c4perren = numpy.zeros(shape=(self.yshape, self.xshape))
            self.CFTs.c3perren = numpy.zeros(shape=(self.yshape, self.xshape))
            self.CFTs.ntfixing = numpy.zeros(shape=(self.yshape, self.xshape))

有没有办法遍历命名元组的元素？我试过这样做，但不起作用：

for fld in self.CFTs._fields:
                self.CFTs.fld= numpy.zeros(shape=(self.yshape, self.xshape))

Answer 1

namedtuple 是一个元组，因此您可以像普通元组一样进行迭代：

>>> from collections import namedtuple
>>> A = namedtuple('A', ['a', 'b'])
>>> for i in A(1,2):
    print i


1
2

但是元组是不可变的，因此您不能更改值

如果您需要字段的名称，您可以使用：

>>> a = A(1, 2)
>>> for name, value in a._asdict().iteritems():
    print name
    print value


a
1
b
2

>>> for fld in a._fields:
    print fld
    print getattr(a, fld)


a
1
b
2

Answer 2

from collections import namedtuple
point = namedtuple('Point', ['x', 'y'])(1,2)
for k, v in zip(point._fields, point):
    print(k, v)

输出：

x 1
y 2

Answer 3

Python 3.6+

您可以像普通元组一样简单地遍历项目：

MyNamedtuple = namedtuple("MyNamedtuple", "a b")
a_namedtuple = MyNamedtuple(a=1, b=2)

for i in a_namedtuple:
    print(i)

从Python 3.6开始，如果你需要属性名字，你现在需要做的是：

for name, value in a_namedtuple._asdict().items()
    print(name, value)

备注

如果您尝试使用 a_namedtuple._asdict().iteritems()，它将抛出 AttributeError: 'collections.OrderedDict' object has no attribute 'iteritems'

遍历 python 中命名元组的元素

Looping over elements of named tuple in python

python

namedtuple

Python 3.6+

备注