为 SpriteKit 转换 UITapGestureRecognizer 的触摸位置 - Swift

Question

我创建了一个游戏 SceneKit scene 变成了 UIViewController。

我实现了这样的 UITapGestureRecognizer :

// TAP GESTURE

let tapGesture = UITapGestureRecognizer(target: self, action: "handleTap:")
sceneView.overlaySKScene?.view!.addGestureRecognizer(tapGesture)

和 handleTap 函数：

func handleTap(sender: UIGestureRecognizer) {

    if sender.state == UIGestureRecognizerState.Ended {

        var touchLocation = sender.locationInView(sender.view)

        touchLocation = self.view.convertPoint(touchLocation, toView: self.view)

        let touchedNode = sceneView.overlaySKScene?.nodeAtPoint(touchLocation)

        if touchedNode == myNode {

            // DO SOMETHING

        }

    }

}

假设myNode的位置是(x: 150.0, y: 150.0)。问题是 touchPosition.y 与 myNode 的 y 位置的 y 位置相反。

如何反转触摸的 y 位置？

谢谢！

Answer 1

试试这个，它对我来说是准确的：-

override func didMoveToView(view: SKView) {

     let tap:UITapGestureRecognizer = UITapGestureRecognizer(target: self, action: Selector("tap:"))
     tap.numberOfTapsRequired = 1

     view.addGestureRecognizer(tap)
}

func tap(sender:UITapGestureRecognizer){

    if sender.state == .Ended {

        var touchLocation: CGPoint = sender.locationInView(sender.view)
        touchLocation = self.convertPointFromView(touchLocation)

    }   
}

为 SpriteKit 转换 UITapGestureRecognizer 的触摸位置 - Swift

Convert touch location of UITapGestureRecognizer for SpriteKit - Swift

ios

swift

touch

scenekit

uitapgesturerecognizer