在 Python 的自动电子邮件脚本中自定义收件人姓名时出错

Question

我尝试编写一个自动将电子邮件发送到电子邮件地址列表的脚本，并希望使用格式化程序自定义正文内容，如下所示：

<html>
Hello {name}, it is me
</html>

所以我写了下面的脚本参考并且没有问题将电子邮件发送给每个收件人 - 但问题是电子邮件正文内容随着收件人数量的增加而累积。例如，列表中的第 4 个收件人最终收到一封包含 4 个正文内容的电子邮件，是第 1、第 2 和第 3 个收件人电子邮件内容的总和。为什么会发生这种情况，我该如何解决？

import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
import time
import random

fromaddr = "sender_gmail_account"

msg = MIMEMultipart()
msg['From'] = fromaddr
msg['Subject'] = "Subject_line"

#list of receivers
s = open("list.txt", "r")
emails = s.readlines()
print emails
s.close()

server = smtplib.SMTP('smtp.gmail.com', 587)
server.starttls()
server.login(fromaddr, "gmail_password")

for address in emails:
    address = address.strip().split(",")      # Removing White spaces.
    toname = address[0]
    toaddr = address[1].strip()
    if toaddr == "":
        continue

    f = open('mail_template.html')
    body = f.read()
    f.close()

    msg['To'] = toaddr
    body = body.format(name=toname)

    msg.attach(MIMEText(body, 'html'))
    text = msg.as_string()
    body = ""
    server.sendmail(fromaddr, toaddr, text)

    rand = random.randrange(2,5)       # Set range of the waiting time.
    time.sleep(rand)

server.quit()

Answer 1

yagmail 非常适合编写 html 电子邮件（本质上，所有电子邮件都是 html 带有简单文本的电子邮件，作为无法处理 html 的浏览器的替代） .请注意，yagmail 还将使登录变得容易，等等。

import yagmail
import random
import time

yag = yagmail.SMTP(fromaddr, 'gmail_password')

template = 'Hello {name}, it is me'           # yagmail automatically makes this HTML
# template = '<h1>Now with big header</h1>'   # other template example     

for address in addresses:
    address = address.strip().split(",")      # Removing White spaces.
    toname = address[0]
    toaddr = address[1].strip()
    if toaddr == "":
        continue

    yag.send(address, "Subject_line", template.format(name=toname))

    time.sleep(random.randrange(2,5))

使用以下方式获取 yagmail：

pip install yagmail

从 48 行增加到 19 行：不错 ;)

完全披露：我是 yagmail 的开发者。

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