如何在 SQL 服务器中将 IPv6 地址从十进制数字字符串转换为两个 bigints？

Question

我有一个包含 IPv6 地址的 CSV 文件，我正试图将其批量导入 sql 服务器 table。 CSV 文件中的地址示例可能是“55828295930114724823525874468560830464”。我希望将 IP 地址存储到数据库中的两个 bigint 中，因为 SQL bigint 只能处理 64 位，而 IPv6 地址需要 128 位。我用于处理 IPV4 地址的导入代码是：

SET @sql = '
    INSERT INTO dbo.IPCountry
    SELECT
        REPLACE(ipFROM, ''"'', '''') AS ipFROM,
        REPLACE(ipTO, ''"'', '''') AS ipTO,
        CAST(REPLACE(countrySHORT, ''"'', '''') AS CHAR(2)) AS countrySHORT
    FROM OPENROWSET(
        BULK ''' + @Directory + 'IPCountry.csv'',
        FORMATFILE = ''' + @Directory + 'IPCountry.Xml''
    ) AS t1
';
exec sp_executesql @sql;

如何将 128 位 IPv6 值转换为两个 bigint 值？

Answer 1

基于您的示例恰好是一个 38 位数字字符串，我会将其分成两半并将每一半转换为 BIGINT 组件。

这是一个演示该过程并将其逆转的示例：

-- Prepare test variables
DECLARE @Source AS NVARCHAR(38)
DECLARE @ipFROMa AS BIGINT
DECLARE @ipFROMb AS BIGINT
DECLARE @Destination AS NVARCHAR(38)

SET @Source = '55828295930114724823525874468560830464'

-- Split Source into TWO strings and then each into a BIGINT
SET @ipFROMa = (SELECT CAST(SUBSTRING(@Source,1,19) AS BIGINT))
SET @ipFROMb = (SELECT CAST(SUBSTRING(@Source,20,19) AS BIGINT))

-- Test returning BIGINTs into one IPv6 string
SET @Destination = (SELECT 
                        CAST( 
                            CAST(@ipFROMa AS NVARCHAR(19)) +
                            CAST(@ipFROMb AS NVARCHAR(19))
                             AS nvarchar(38)))

-- Display the values for verification
SELECT @Source, @ipFROMa, @ipFROMb, @Destination

结果：

55828295930114724823525874468560830464 5582829593011472482 3525874468560830464 55828295930114724823525874468560830464

如何在 SQL 服务器中将 IPv6 地址从十进制数字字符串转换为两个 bigints？

How to convert an IPv6 address from decimal number string to two bigints in SQL Server?

sql-server

csv

ipv6

bigint