如何输入多个动态数组整数?
How do I input more than one dynamic array integer?
如何修改此代码以便我可以输入多个系数?
我想我可以输入类似“3 2 1”的内容,空格应该不会影响我的用户输入,但我不确定该怎么做。
这是我目前的代码:
#include <iostream>
using namespace std;
int *foil(int A[], int B[], int co, int coo)
{
int *product = new int[co+coo-1];
for (int i = 0; i<co+coo-1; i++)
product[i] = 0;
for (int i=0; i<coo; i++)
{
for (int j=0; j<co; j++)
product[i+j] += A[i]*B[j];
}
return product;
}
void printPoly(int poly[], int co)
{
for (int i=0; i<co; i++)
{
cout << poly[i];
if (i != 0)
cout << "x^" << i ;
if (i != co-1)
cout << " + ";
}
}
int main()
{
int co, coo;
int *A;
A=new int[co];
int *B;
B=new int[coo];
cout << "How many coefficients are in the first poly?: ";
cin >> co;
cout << "What are the coefficients? (Lowest power first): ";
cin >> *A;
cout << "How many coefficients are in the second poly?: ";
cin >>coo;
cout << "What are the coefficients? (Lowest power first): ";
cin >>*B;
printPoly(A, coo);
cout << "\n";
cout << "times" << endl;
printPoly(B, co);
cout << "\n";
cout << "-----" << endl;
int *product = foil(A, B, co, coo);
printPoly(product, co+coo-1);
return 0;
}
它输出这个:
How many coefficients are in the first poly?: 3
What are the coefficients? (Lowest power first): 3 2 1
How many coefficients are in the second poly?: What are the coefficients? (Lowest power first): 3 + 0x^1
times
1 + 0x1 + 0x^2
-----
3 + 0x^1 + 0x^2 + 0x^3
我希望它这样输出:
How many coefficients are in the first poly?: 3
What are the coefficients? (Lowest power first): 3 2 1
How many coefficients are in the second poly? 3
What are the coefficients? (Lowest power first): 1 2 1
3 + 2x^1 + 1x^2
times
1 + 2x^1 + 1x^2
-----
3 + 8x^1 + 8x^2 + 4x^3 + 1x^4
你需要循环输入。
这是你可以做到的。
cout << "How many coefficients are in the first poly?: ";
cin >> co;
cout << "What are the coefficients? (Lowest power first): ";
for(int i=0;i<co;i++)
cin >> *(A+i);
cout << "How many coefficients are in the second poly?: ";
cin >>coo;
cout << "What are the coefficients? (Lowest power first): ";
for(int i=0;i<coo;i++)
cin >>*(B+i);
printPoly(A, coo);
cout << "\n";
cout << "times" << endl;
printPoly(B, co);
cout << "\n";
cout << "-----" << endl;
int *product = foil(A, B, co, coo);
printPoly(product, co+coo-1);
getch();
return 0;
这是输出图像
如何修改此代码以便我可以输入多个系数?
我想我可以输入类似“3 2 1”的内容,空格应该不会影响我的用户输入,但我不确定该怎么做。
这是我目前的代码:
#include <iostream>
using namespace std;
int *foil(int A[], int B[], int co, int coo)
{
int *product = new int[co+coo-1];
for (int i = 0; i<co+coo-1; i++)
product[i] = 0;
for (int i=0; i<coo; i++)
{
for (int j=0; j<co; j++)
product[i+j] += A[i]*B[j];
}
return product;
}
void printPoly(int poly[], int co)
{
for (int i=0; i<co; i++)
{
cout << poly[i];
if (i != 0)
cout << "x^" << i ;
if (i != co-1)
cout << " + ";
}
}
int main()
{
int co, coo;
int *A;
A=new int[co];
int *B;
B=new int[coo];
cout << "How many coefficients are in the first poly?: ";
cin >> co;
cout << "What are the coefficients? (Lowest power first): ";
cin >> *A;
cout << "How many coefficients are in the second poly?: ";
cin >>coo;
cout << "What are the coefficients? (Lowest power first): ";
cin >>*B;
printPoly(A, coo);
cout << "\n";
cout << "times" << endl;
printPoly(B, co);
cout << "\n";
cout << "-----" << endl;
int *product = foil(A, B, co, coo);
printPoly(product, co+coo-1);
return 0;
}
它输出这个:
How many coefficients are in the first poly?: 3
What are the coefficients? (Lowest power first): 3 2 1
How many coefficients are in the second poly?: What are the coefficients? (Lowest power first): 3 + 0x^1
times
1 + 0x1 + 0x^2
-----
3 + 0x^1 + 0x^2 + 0x^3
我希望它这样输出:
How many coefficients are in the first poly?: 3
What are the coefficients? (Lowest power first): 3 2 1
How many coefficients are in the second poly? 3
What are the coefficients? (Lowest power first): 1 2 1
3 + 2x^1 + 1x^2
times
1 + 2x^1 + 1x^2
-----
3 + 8x^1 + 8x^2 + 4x^3 + 1x^4
你需要循环输入。 这是你可以做到的。
cout << "How many coefficients are in the first poly?: ";
cin >> co;
cout << "What are the coefficients? (Lowest power first): ";
for(int i=0;i<co;i++)
cin >> *(A+i);
cout << "How many coefficients are in the second poly?: ";
cin >>coo;
cout << "What are the coefficients? (Lowest power first): ";
for(int i=0;i<coo;i++)
cin >>*(B+i);
printPoly(A, coo);
cout << "\n";
cout << "times" << endl;
printPoly(B, co);
cout << "\n";
cout << "-----" << endl;
int *product = foil(A, B, co, coo);
printPoly(product, co+coo-1);
getch();
return 0;
这是输出图像