添加更多条件以在 mysql - google 地图中查找附近的地点

Question

我正在尝试使用我在 google 的文档 here

中找到的解决方案找到附近的地方

问题是我想在搜索中添加更多过滤器

原解

$sql2 = "SELECT *, ( 3959 * acos( cos( radians(" . $row1['tubeLan'] . ") ) * cos( radians( mapLan ) ) * cos( radians( mapLon ) - radians(" . $row1['tubeLon'] . ") ) + sin( radians(" . $row1['tubeLan'] . ") ) * sin( radians( mapLan ) ) ) ) AS distance FROM " . $table . " HAVING distance < 2500 ORDER BY distance LIMIT 0 , 20;

我想让它在上面的语句中添加这个过滤器

SIZE between $firstrange and $secondrange"

我试过了，但没有提供所需的结果

$sql2 = "SELECT *, ( 3959 * acos( cos( radians(" . $row1['tubeLan'] . ") ) * cos( radians( mapLan ) ) * cos( radians( mapLon ) - radians(" . $row1['tubeLon'] . ") ) + sin( radians(" . $row1['tubeLan'] . ") ) * sin( radians( mapLan ) ) ) ) AS distance FROM " . $table . " HAVING distance < 2500 ORDER BY distance LIMIT 0 , 20 and SIZE between $firstrange and $secondrange";

我在这里做错了什么？我不能通过在它们之间放置 AND 来添加这些条件吗？

Answer 1

当然可以使用 AND 添加条件，但必须将它们添加到 WHERE 或 HAVING 子句中，而不是在语句的末尾：

SELECT *, 
( 3959 * acos( cos( radians(" . $row1['tubeLan'] . ") ) * cos( radians( mapLan  ) ) * cos( radians( mapLon ) - radians(" . $row1['tubeLon'] . ") ) + sin( radians(" . $row1['tubeLan'] . ") ) * sin( radians( mapLan ) ) ) ) AS distance 
FROM " . $table . " 
WHERE SIZE between $firstrange and $secondrange
HAVING distance < 2500 ORDER BY distance LIMIT 0 , 20 ;

（我想 SIZE 是你 table 中的一列）

添加更多条件以在 mysql - google 地图中查找附近的地点

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