main() 函数不会输出 coin_to_bag 的值

Question

我收到以下错误：

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File ".\file.py", line 113, in <module>
    main()
  File ".\file.py", line 111, in main
    cs_in_the_b = assign_c2b(bs, cs, c2b)
NameError: global name 'c2b' is not defined

当我运行我的代码：

cs = ['quarter','dime','nickel']
bs = ['sm','med','lg']

def assign_c2b(bs, cs):
    '''
    assign_c2b() assigns cs to bs
    specifically c2b{} stores this association between the c and b
    '''
    c2b = {}#'test'}
    print('Here are your bs:\n')
    print(bs)
    print('\n')
    print('Here are your c types:\n')
    print (cs)

    for b in bs:
        c_type = input('Number of this type?    e.g. type 1 for Quarter "["Quarter", "Nickel"]" ')  #e.g. 0.25 * 2
        c_amount = input('Number of this type?  e.g. 15')  #e.g. 0.25 * 2
        for c in cs:
            c2b[b] = [c_type, c_amount]

    print(c2b)

    return (c2b)


def main():
    bs = gather_b()
    cs = gather_c()
    cs_in_the_b = assign_c2b(bs, cs, c2b)

main()

我只是想让我的 var c2b 在 main() 中调用时显示一些内容。也许我完全忽略了原因，但一直无法弄清楚。有人可以帮忙吗？谢谢！！

Answer 1

def main():
    bags = gather_bag()
    coins = gather_coin()
    coins_in_the_bag = assign_coin_to_bag(bags, coins, coin_to_bag)

调用 assign_coin_to_bag.

时从未定义

coin_to_bag

即使已定义，assign_coin_to_bag 也需要 2 个参数（def assign_coin_to_bag(bags, coins) 但您正试图用 3 个参数调用它。

main() 函数不会输出 coin_to_bag 的值

main() function will not output value for coin_to_bag

python

dictionary

main