将数组索引增加 1 C#

Question

我有一个用于计数的整数数组。

将整数数组的某个索引增加 1 的最简单方法是什么？

我的代码目前看起来像这样。

input = Convert.ToInt32(textBox1.Text);
number1 = rand.Next(1, 7);
number2 = rand.Next(1, 7);
number3 = rand.Next(1, 7);

//array used to keep track of how many times a certain number has showed up
int[] counters = new int[14];

int sum = number1 + number2 + number3;

for (int i = 0; i <= input; i++)
{

    counters[sum] = counters[sum] + 1; //counters[sum]++;???
}

for (int i = 0; i < 14; i++)
{
    richTextBox1.Text += "The number " + (i + 1) + "showed up" + counters[i] + " times\n";
}

我做错了什么？为什么我做不到：

array[i]++;    or     array[i] = array[i] + 1; ???

为清楚起见进行编辑。

我想做什么：

根据用户的意愿掷 3 个骰子

将 3 个骰子掷在一起（总和应在 3 -18 之间）然后记录每个总和出现的频率。

然后最后以百分比显示每个数字出现的次数。

Answer 1

您可以使用 linq 和 List 来执行此操作，请参阅此代码：

input = Convert.ToInt32(textBox1.Text);

for(var i = 0; i < input; i++)
{
    number1 = rand.Next(1, 7);
    number2 = rand.Next(1, 7);
    number3 = rand.Next(1, 7);

    //array used to keep track of how many times a certain number has showed up
    int sum = number1 + number2 + number3;
    sums.Add(sum); //Where sums is a List<int>
}
var report = sums.GroupBy(i => i).Select(g => new { TimesShowedUp = g.Count(), Sum = g.Key });

foreach(var r in report)
{
    richTextBox1.Text += "The number " + r.Sum + "showed up" + r.TimesShowedUp + " times\n";
}

Answer 2

听起来你真正想要的是以下内容。

Random rand = new Random();
int numberOfRolls = Convert.ToInt32(textBox1.Text);
int[] counters = new int[16]; //16 different possible sums (3 to 18)

for (int i = 0; i < numberOfRolls; i++)
{
    int sum = rand.Next(1, 7) + rand.Next(1, 7) + rand.Next(1, 7);
    counters[sum - 3]++;
}

for (int i = 0; i < 16; i++)
{
    richTextBox1.Text += "The number " + (i + 3) + " showed up " + counters[i] + " times\n";
}

这需要从 textBox1 开始滚动的次数，然后循环该次数从 3 个随机数 (1-6) 中创建 sum。并递增数组中的相应位置。由于有 16 种可能性，数组被初始化为该大小，您只需减去 3 即可将总和转换为索引，然后在打印时加 3 即可转换回来。

Answer 3

//array used to keep track of how many times a certain number has showed up
int[] counters = new int[15];

iterations = Convert.ToInt32(textBox1.Text);

for (int i = 1; i <= iterations; i++)
{
    number1 = rand.Next(1, 7);
    number2 = rand.Next(1, 7);
    number3 = rand.Next(1, 7);

    int sum = number1 + number2 + number3;

    counters[sum-3]++;
}

for (int i = 0; i <= 15; i++)
{
    richTextBox1.Text += "The number " + (i + 3) + " showed up " + counters[i] + " times\n";
}

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