如何在 readline python 中添加新标签

Question

我无法在阅读文件中添加新选项卡。
我试过 readline，但我很困惑..

f = open('data.txt', 'r')
count = 0
for i in f.readlines():
     count += 1
     if count == 3:
          #adding new tab
     print i,

在这里，我有 data.txt，其中包含这样的数据：

af  Afrikaans
sq  Albanian
ar  Arabic
hy  Armenian
az  Azerbaijani
eu  Basque

但是如果数据在特定的计数读取行中，我无法添加新标签。
我想做成这样..

af  Afrikaans      hy   Armenian
sq  Albanian       az   Azerbaijani
ar  Arabic         eu   Basque

Answer 1

您可以创建一个列表来存储每 3 次迭代的行，然后将其附加到 last_q，最后您可以使用 zip 函数压缩 last_q 并加入对使用 \t 然后再次写入文件：

import copy
q = []
last_q= []
with open('newefile.txt','r') as f:
   for line in f:
        q.append(line.strip())
        if len(q)==3 :
            last_q.append(copy.copy(q))
            q=[]

with open('newefile.txt','w') as f:
    for lines in zip(*last_q) :
        print lines
        f.write('\t'.join(lines)+'\n')

演示：

print last_q    
deque([deque(['af  Afrikaans\thy  Armenian', 'sq  Albanian\taz  Azerbaijani', 'ar  Arabic\teu  Basque'], maxlen=3)]) 

print zip(*last_q)
[('af  Afrikaans', 'hy  Armenian'), ('sq  Albanian', 'az  Azerbaijani'), ('ar  Arabic', 'eu  Basque')]

最终结果：

af  Afrikaans   hy  Armenian
sq  Albanian    az  Azerbaijani
ar  Arabic      eu  Basque

Answer 2

我想你想要的实际上是在同一行上打印两行不同的行，用制表符分隔。所以你必须阅读所有内容，然后打印它们并在中间插入标签。像这样：

f = open('data.txt', 'r')
lines = []
for i in f.readlines():
    lines.append(i.replace("\n", ""))

for i in range(0, len(lines)/2):
   print lines[i] +  "\t" + lines[len(lines)/2 + i]

Answer 3

下面是将完成您的目标的代码，希望它是您想要的：

f = open('data.txt','r')
lines = [l.strip() for l in f.readlines()]
l = len(lines)
for i in range(l/2):
    print lines[i]+'\t'+ lines[i + l/2]
if l%2: #if it is odd
    print lines[-1]

Answer 4

我特别喜欢 itertools grouper 这样的食谱。

from itertools import zip_longest
# in Python2 do:
## from itertools import izip_longest

data = """af  Afrikaans
sq  Albanian
ar  Arabic
hy  Armenian
az  Azerbaijani
eu  Basque""".splitlines()

def grouper(iterable, n, fillvalue=None):
    "Collect data into fixed-length chunks or blocks"
    # grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx"
    args = [iter(iterable)] * n
    return zip_longest(*args, fillvalue=fillvalue)

for line in zip(*grouper(data, 3, '')):
    print('\t'.join(line))

这可以很好地模块化

# tablefy.py

from itertools import zip_longest

def rows(data, max_rows=None, columndelimiter="\t"):
    """Produces rows, squeezing extra data into max_rows by
    adding columns delimited by columndelimiter"""
    # rows(['a','b','c','d'], 3, "    ") --> ['a    d', 'b    ', 'c    ']

    if max_rows is None:
        return (row for row in data)

    def _grouper(iterable, n, fillvalue=None):
        """Collect data into fixed-length chunks or blocks"""
        # grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx
        args = [iter(iterable)] * n
        return zip_longest(*args, fillvalue=fillvalue)

    for line in _grouper(data, max_rows, fillvalue=""):
        yield "\t".join(line)

# my_file.py

data = """af  Afrikaans
sq  Albanian
ar  Arabic
hy  Armenian
az  Azerbaijani
eu  Basque""".splitlines()

import tablefy

for row in tablefy.rows(data, max_rows=3):
    print(row)

如何在 readline python 中添加新标签

how to adding new tab in readline python

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readlines