难以理解 many-to-many 递归

Question

CREATE TABLE PERSON
(
    persID      INT IDENTITY(1,1)   PRIMARY KEY,
    persFName   VARCHAR(30) NOT NULL,
    persLName   VARCHAR(30) NOT NULL, 
    persDOB     DATE,
    motherID    INT FOREIGN KEY REFERENCES person(persID),
    fatherID    INT FOREIGN KEY REFERENCES person(persID),
    persDOD     DATE,
    persGender  CHAR(1),
)

CREATE TABLE COUPLE
(
    coupleID    INT     IDENTITY(1,1)   PRIMARY KEY,
    alphaSpouse INT     NOT NULL    FOREIGN KEY REFERENCES person(persID),
    omegaSpouse INT     NOT NULL    FOREIGN KEY REFERENCES person(persID),
    coupleStart DATE    NOT NULL,
    coupleEnd   DATE,
)

在过去的几个小时里，我一直在想办法输出每个父亲、母亲和他们所有的 children。 Trying to get an output like this

我知道如何单独显示一组，如下所示

SELECT *
FROM person
WHERE persID IN (select fatherID from person
                    WHERE fatherID IS NOT NULL)

但我一辈子都想不出如何将它们一起展示（同时相互关联）。我使用交叉连接吗？联合所有？

Answer 1

这只是一个连接，几次。与 couple table:

无关

select (f.persFname + ' ' + f.persLname) as father,
       (m.persFName + ' ' + m.persLname) as mother,
       (c.persFName + ' ' + c.persLname) as child
from person c join
     person m  -- mother
     on c.motherid = m.persid join
     person f  -- father
     on c.fatherid = f.persid;

难以理解 many-to-many 递归

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sql-server

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sql-server-2012