选择问题 (list/multilist) codenameone

Question

我执行了以下操作以获取以 watchVideo 形式显示的列表中所选项目的 json 值...但是无论如何我也可以获得下一个列表项的值所以我可以在watchVideo形式中设置下一个按钮并直接播放下一个视频...

    findYoutubeMultiList(f).setModel(new com.codename1.ui.list.DefaultListModel(mData));
        findYoutubeMultiList(f).addActionListener((e) -> {
                    selection = (Map<String, String>) findYoutubeMultiList(f).getSelectedItem();
indexSelection = findYoutubeMultiList(f).getSelectedIndex();
**//i can get the index of selected item by above indexSelection but how to get the value of the incremented index??**
                    showForm("WatchVideo", null);
                });

已编辑：

 for (int i = 0; i < response.size(); i++) {
                        Hashtable hm = (Hashtable) response.get(i);
                        Hashtable snippet = (Hashtable) hm.get("snippet");
                        HashMap<String, Object> m = new HashMap<String, Object>();
                        videoResource = (Hashtable) snippet.get("resourceId");
                        videoId = videoResource.get("videoId").toString();
                        m.put("video", videoId);
                        mData.add(m);
                    }

观看视频表格：

protected void beforeWatchVideo(Form f) {

        for (int i = 0; i < mData.size(); i++) {
            //how to get the position of selection and more
 importantly how to get the values of incremented index
        }

Answer 1

遍历多列表的源并获取所选项目的索引，然后只需增加索引并获取该索引处的值，如果您想播放上一个则减少。

记得将索引与 0 和源长度进行比较，以避免 NullPointer。

选择问题 (list/multilist) codenameone

Selection issue (list/multilist) codenameone

codenameone