如何为结构数组中的 char 字符串分配内存？

Question

我将要创建一个将学生数据存储在列表中的程序。我的问题是，我应该如何为我的结构数组中的每个 char 字符串分配内存。我的代码在下面。如有其他错误，请指正。

#include <stdio.h>
#include <stdlib.h>
#define DATA 10;
#define NAME 10;

typedef struct{
int id;
char *givenname;
char *familyname;

} students;

int main()
{
int answer;
int incr = 0; // Index for students in the list
int datalen = DATA;
int namelen = NAME;

students *studentlist;
studentlist = malloc(datalen * sizeof(students)); // Allocate memory for first ten students

if(NULL == studentlist){
    printf("Error: Couldn't allocate memory\n");
    exit(0);
}

for(incr = 0; incr < datalen; incr ++){
    printf("Add student to the list? Yes(1) No(2)\n");
    scanf("%d", &answer);

    if(answer != 1){
        break;
    }

    studentlist[incr]->givenname = malloc(namelen * sizeof(char)); // Allocate memory for each name
    studentlist[incr]->familyname = malloc(namelen * sizeof(char));

    printf("Insert ID: ");
    scanf("%d", &studentlist[incr].id);

    printf("Insert given name: \n");
    scanf("%s", studentlist[incr].givenname);

    printf("Insert family name: \n");
    scanf("%s", studentlist[incr].familyname);


}

free(studentlist);
free(studentlist.givename);
free(studentlist.familyname);


return 0;
}

Answer 1

部分元素引用错误：

studentlist[incr]->givenname

应该是：

studentlist[incr].givenname

字符串分配似乎没问题。

您的释放代码需要更改：

free(studentlist);
free(studentlist.givename);
free(studentlist.familyname);

您需要循环释放 studentlist.givename 和 studentlist.familyname，然后在最后释放学生列表：

for(incr = 0; incr < datalen; incr ++){
   free(studentlist[incr].givename);
   free(studentlist[incr].familyname);
}
free(studentlist);

如何为结构数组中的 char 字符串分配内存？

How to allocate memory for char strings in a struct array?

c

arrays

struct

dynamic-memory-allocation