为什么 watch 任务在 gulp 中终止已经使用了 gulp-plumber 插件？

Question

我尝试在 gulp (gulp-plumber) 中使用这个插件。我研究了这个插件，它给你错误但它观察状态不是 stop.In 换句话说它在命令 line.But 上给出你的文件错误，它不会停止观看。 https://www.npmjs.com/package/gulp-plumber

但是当我在 sass 文件中更改时尝试在 saas 文件上创建错误，然后它停止监视然后再次我需要给出命令为什么？

这里是我的 gulp 文件。

var gulp = require('gulp');
//require sass package
var sass = require('gulp-sass');
var rename = require('gulp-rename');
var minifyCss = require('gulp-minify-css');
var uglify = require('gulp-uglify');
var concat = require('gulp-concat');
var plumber = require('gulp-plumber');




// Compile Our Sass
gulp.task('sass', function () {
    return gulp.src('scss/*.scss')
        .pipe(sass())
        .pipe(plumber())
        .pipe(gulp.dest('css'));
});
// css miifilcation
gulp.task('minify-css',['sass'], function () {
    return gulp.src('css/*.css')
        .pipe(minifyCss())
        .pipe(plumber())
        .pipe(rename({suffix: '.min'}))
        .pipe(gulp.dest('dist'));
});

// js minifiction
gulp.task('compress', function() {
    return gulp.src('app/**/*.js')
        .pipe(uglify())
        .pipe(gulp.dest('jdist'));
});

//concatination of js files

gulp.task('scripts', function() {
    return gulp.src('jdist/**/*.js')
        .pipe(concat('all.js'))
        .pipe(rename({suffix: '.min'}))
        .pipe(gulp.dest('dist/'));
});


// Watch Files For Changes
gulp.task('watch', function () {
    gulp.watch('scss/*.scss', ['sass','minify-css']);
});

gulp.task('default', ['sass', 'watch', 'minify-css','scripts']);

这些是我执行的步骤。

在命令行写gulp
更改 sass 文件。在 saas 文件中删除一个 '{ 然后它给出错误并终止为什么？

这是我的日志

Microsoft Windows [Version 6.1.7601]
Copyright (c) 2009 Microsoft Corporation.  All rights reserved.

D:\Webapplication\DemoApp>gulp
[09:11:47] Using gulpfile D:\Webapplication\DemoApp\gulpfile.js
[09:11:47] Starting 'sass'...
[09:11:47] Starting 'watch'...
[09:11:47] Finished 'watch' after 9.13 ms
[09:11:47] Starting 'scripts'...
[09:11:47] Finished 'sass' after 53 ms
[09:11:47] Starting 'minify-css'...
[09:11:47] Finished 'minify-css' after 27 ms
[09:11:47] Finished 'scripts' after 61 ms
[09:11:47] Starting 'default'...
[09:11:47] Finished 'default' after 7.5 µs
[09:13:23] Starting 'sass'...

events.js:141
      throw er; // Unhandled 'error' event
      ^
 Error: scss\home.scss
Error: Invalid CSS after "}": expected "}", was ""
        on line 28 of stdin
>> }
   ^

    at options.error (D:\Webapplication\DemoApp\node_modules\gulp-sass\node_modules\node-sass\lib\index.js:277:32)

D:\Webapplication\DemoApp>

在 answer.I 应用你的答案后更新问题。它没有终止但在它之后也没有观看方式？

Microsoft Windows [Version 6.1.7601]
Copyright (c) 2009 Microsoft Corporation.  All rights reserved.

D:\Webapplication\DemoApp>gulp
[10:43:28] Using gulpfile D:\Webapplication\DemoApp\gulpfile.js
[10:43:28] Starting 'watch'...
[10:43:28] Finished 'watch' after 20 ms
[10:43:28] Starting 'default'...
[10:43:28] Finished 'default' after 7.11 µs
[10:43:42] Starting 'sass'...
[10:43:42] Finished 'sass' after 32 ms
[10:43:42] Starting 'minify-css'...
[10:43:42] Finished 'minify-css' after 30 ms
[10:43:49] Starting 'sass'...
[10:43:49] Plumber found unhandled error:
 Error in plugin 'gulp-sass'
Message:
    scss\home.scss
Error: Invalid CSS after "}": expected "}", was ""
        on line 28 of stdin
>> }
   ^

Details:
    formatted: Error: Invalid CSS after "}": expected "}", was ""
        on line 28 of stdin
>> }
   ^

    column: 1
    line: 28
    file: stdin
    status: 1
    messageFormatted: scss\home.scss
Error: Invalid CSS after "}": expected "}", was ""
        on line 28 of stdin
>> }
   ^

Answer 1

尝试在 sass 任务中交换 sass 和管道工，如 gulp 管道工页面上的示例所示。你的任务应该是这样的

// Compile Our Sass
gulp.task('sass', function () {
    return gulp.src('scss/*.scss')
        .pipe(plumber({
              handleError: function (err) {
                               console.log(err);
                               this.emit('end');
                           }
         }))
        .pipe(sass())
        .pipe(gulp.dest('css'));
});

更新

为了简化我的回答，我去掉了 js 任务。现在您正在编译 sass，将其缩小并在单个任务中将 min 添加到名称中。

// SASS 
gulp.task('sass', function () {
    return gulp.src('scss/*.scss')
        .pipe(plumber())
        .pipe(sass({outputStyle: 'compressed'}))
        .pipe(rename({suffix: '.min'}))
        .pipe(gulp.dest('dist'));
});


// Watch Files For Changes
gulp.task('watch', function () {
    gulp.watch('scss/*.scss', ['sass']);
});

gulp.task('default', ['sass', 'watch']);

为什么 watch 任务在 gulp 中终止已经使用了 gulp-plumber 插件？

Why watch task terminate in gulp already use gulp-plumber plugin?

javascript

angularjs

angularjs-directive

gulp

gulp-watch