从文件中读取 C++ Ifstream
Reading from a file C++ Ifstream
我正在尝试使用动态规划来做一个问题,以在最大化价值的同时,在一定重量下从文本文件中找到哪些项目 select。文件格式为:
item1, weight, value
item2, weight, value
项目数量可变。我在 main 方法中读取文件时遇到问题,我正在尝试对错误输入进行错误检查。我的问题来自于我检查重量是否丢失,或者是一个字符串而不是一个整数。我不知道如何单独检查一个字符串,或者那个地方是否没有任何内容。我应该根据错误输出不同的错误。谢谢
int main(int argc, char * const argv[])
{
std::vector<Item> items;
if (argc != 3)
{
std::cerr << "Usage: ./knapsack <capacity> <filename>";
return -1;
}
int capacity;
std::stringstream iss(argv[1]);
if (!(iss >> capacity) || (capacity < 0))
{
std::cerr << "Error: Bad value '" << argv[1] << "' for capacity." << std::endl;
return -1;
}
std::ifstream ifs(argv[2]);
if (ifs.is_open())
{
std::string description;
unsigned int weight;
unsigned int value;
int line = 1;
while (!ifs.eof())
{
if (!(ifs >> description))
{
std::cerr << "Error: Line number " << line << " does not contain 3 fields." << std::endl;
return -1;
}
if (!(ifs >> weight))
{
if (ifs.eof())
std::cerr << "Error: Line number " << line << " does not contain 3 fields." << std::endl;
else
std::cerr << "Error: Invalid weight '" << ifs << "' on line number " << line << "." << std::endl;
return -1;
}
else if (!(ifs >> weight) || (weight < 0))
{
std::cerr << "Error: Invalid weight '" << ifs << "' on line number " << line << "." << std::endl;
return -1;
}
if (!(ifs >> value))
{
if (ifs.eof())
std::cerr << "Error: Line number " << line << " does not contain 3 fields." << std::endl;
else
std::cerr << "Error: Invalid value '" << ifs << "' on line number " << line << "." << std::endl;
return -1;
}
else if (!(ifs >> value) || (value < 0))
{
std::cerr << "Error: Invalid value '" << ifs << "' on line number " << line << "." << std::endl;
return -1;
}
Item item = Item(line, weight, value, description);
items.push_back(item);
line++;
}
ifs.close();
knapsack(capacity, items, items.size());
}
else
{
std::cerr << "Error: Cannot open file '" << argv[2] << "'." << std::endl;
return -1;
}
return 0;
}
您可以一次读取整行并使用正则表达式检查其格式。
我认为更好的方法是使用 getline
函数,通过该函数您可以获取一整行,然后您可以尝试将其拆分为三个字符串。如果找不到三个部分或三个部分中的任何一个格式不正确,您可以输出错误。
示例代码如下,
#include<fstream>
#include<iostream>
#include<vector>
#include <sstream>
#include<string>
using namespace std;
void split(const std::string &s, std::vector<std::string> &elems, char delim) {
elems.clear();
std::stringstream ss(s);
std::string item;
while (std::getline(ss, item, delim)) {
elems.push_back(item);
}
}
int main()
{
vector<string> elems;
ifstream fi("YOUR\PATH");
string inp;
while(getline(fi, inp))
{
split(inp, elems, ' ');
if(elems.size() != 3)
{
cout<<"error\n";
continue;
}
int value;
bool isint = istringstream(elems[1])>>value;
if(!isint)
{
cout << "error\n";
continue;
}
cout<<"value was : " << value << endl;
}
return 0;
}
我正在尝试使用动态规划来做一个问题,以在最大化价值的同时,在一定重量下从文本文件中找到哪些项目 select。文件格式为:
item1, weight, value
item2, weight, value
项目数量可变。我在 main 方法中读取文件时遇到问题,我正在尝试对错误输入进行错误检查。我的问题来自于我检查重量是否丢失,或者是一个字符串而不是一个整数。我不知道如何单独检查一个字符串,或者那个地方是否没有任何内容。我应该根据错误输出不同的错误。谢谢
int main(int argc, char * const argv[])
{
std::vector<Item> items;
if (argc != 3)
{
std::cerr << "Usage: ./knapsack <capacity> <filename>";
return -1;
}
int capacity;
std::stringstream iss(argv[1]);
if (!(iss >> capacity) || (capacity < 0))
{
std::cerr << "Error: Bad value '" << argv[1] << "' for capacity." << std::endl;
return -1;
}
std::ifstream ifs(argv[2]);
if (ifs.is_open())
{
std::string description;
unsigned int weight;
unsigned int value;
int line = 1;
while (!ifs.eof())
{
if (!(ifs >> description))
{
std::cerr << "Error: Line number " << line << " does not contain 3 fields." << std::endl;
return -1;
}
if (!(ifs >> weight))
{
if (ifs.eof())
std::cerr << "Error: Line number " << line << " does not contain 3 fields." << std::endl;
else
std::cerr << "Error: Invalid weight '" << ifs << "' on line number " << line << "." << std::endl;
return -1;
}
else if (!(ifs >> weight) || (weight < 0))
{
std::cerr << "Error: Invalid weight '" << ifs << "' on line number " << line << "." << std::endl;
return -1;
}
if (!(ifs >> value))
{
if (ifs.eof())
std::cerr << "Error: Line number " << line << " does not contain 3 fields." << std::endl;
else
std::cerr << "Error: Invalid value '" << ifs << "' on line number " << line << "." << std::endl;
return -1;
}
else if (!(ifs >> value) || (value < 0))
{
std::cerr << "Error: Invalid value '" << ifs << "' on line number " << line << "." << std::endl;
return -1;
}
Item item = Item(line, weight, value, description);
items.push_back(item);
line++;
}
ifs.close();
knapsack(capacity, items, items.size());
}
else
{
std::cerr << "Error: Cannot open file '" << argv[2] << "'." << std::endl;
return -1;
}
return 0;
}
您可以一次读取整行并使用正则表达式检查其格式。
我认为更好的方法是使用 getline
函数,通过该函数您可以获取一整行,然后您可以尝试将其拆分为三个字符串。如果找不到三个部分或三个部分中的任何一个格式不正确,您可以输出错误。
示例代码如下,
#include<fstream>
#include<iostream>
#include<vector>
#include <sstream>
#include<string>
using namespace std;
void split(const std::string &s, std::vector<std::string> &elems, char delim) {
elems.clear();
std::stringstream ss(s);
std::string item;
while (std::getline(ss, item, delim)) {
elems.push_back(item);
}
}
int main()
{
vector<string> elems;
ifstream fi("YOUR\PATH");
string inp;
while(getline(fi, inp))
{
split(inp, elems, ' ');
if(elems.size() != 3)
{
cout<<"error\n";
continue;
}
int value;
bool isint = istringstream(elems[1])>>value;
if(!isint)
{
cout << "error\n";
continue;
}
cout<<"value was : " << value << endl;
}
return 0;
}