根据国家/地区合并多个 IPv4 地址块
merging of multiple IPv4 address blocks on the basis of their country region
我有 CIDR 表示法形式的 IPv4 块。这些街区是根据城市划分的 我想将它们合并到一个级别 我的意思是直到区域级别
例如
12.17.230.48|12.178.230.63|US|Texas|Temple
12.178.230.64|12.178.230.95|US|Texas|Abilene
12.178.230.96|12.178.230.111|US|Texas|Jayton
12.178.230.112|12.178.230.119|US|Texas|Wichita Falls
12.178.230.120|12.178.230.127|US|Texas|Mansfield
12.178.230.128|12.178.230.159|US|Texas|Waco (Bellmead)
12.178.230.160|12.178.230.167|US|Texas|Irving
12.178.230.168|12.178.230.175|US|Texas|Fort Worth
12.178.230.176|12.178.230.183|US|Texas|Alvarado
12.178.230.184|12.178.230.191|US|Texas|Weatherford
12.178.230.192|12.178.230.199|US|Texas|Haltom City
12.178.230.200|12.178.230.207|US|Texas|Fort Worth (Diamond Hill - Jarvis)
12.178.230.208|12.178.230.223|US|Texas|Fort Worth
12.178.230.224|12.178.230.231|US|Texas|Coppell
12.178.230.232|12.178.230.239|US|Texas|Lubbock
这里所有的都去德州所以我想像这样把所有这些块合并成一个
start_ip_of_first_range|end_ip_of_last_range_of_same_region|US|Texas
虽然我尝试过,但看起来我什至违反了 IPv4 地址基本规则
请推荐任何公式?
好吧,您只需要确定 'supernet' 的最低和最高 IP 子网即可。
12.178.230.48|12.178.230.63|US|Texas|Temple
12.178.230.232|12.178.230.239|US|Texas|Lubbock
因此,要将它们分组,您需要找到包含这些范围的子网掩码。您可以使用的唯一子网掩码是 /24。 /25 只会为您提供范围从 12.178.230.0-12.178.230.127
或 12.178.230.128-12.178.230.255
.
的 'supernet'
A /24 子网掩码为您提供以下范围:12.178.230.0-12.178.230.255
Extra: supernet might not be the correct naming convention, but it gives you a general idea that this is the global IP range for all your
results.
好吧,写到这里已经晚了,但是我找到了一个简单而冗长的方法来实现这个objective。
1. First convert all the ranges in the form of network_address|subnet_mask
2. sort whole the file in descending IP address
3. Now check if two lines fulfill following conditions
a. Same subnet mast &&
b. Re-Check network IP if the position of first set bit from right is greater than host bit length &&
c. Network IP of the line = network ip of next line + 2^(number of host bit) +1 &&
d. First set bit from right in first line should be equal and less than the first set bit in next line's IP. &&
e. Both line should have same location &&
4. In that case remove the next line and decrease the subnet mask length by one.
5. Now the resultant range will serve exactly same IP addresses as much the initial two ranges were serving neither more or less .
6. To make more merging keep repeating step 2 to 5
我使用 C 程序和 bash 实用程序完成了这项工作。虽然我没有在这里粘贴程序如果有人需要它我会尽量把确切的解决方案放在这里。
这可能是著名问题的解决方案 http://www.perlmonks.org/?node_id=118346
我有 CIDR 表示法形式的 IPv4 块。这些街区是根据城市划分的 我想将它们合并到一个级别 我的意思是直到区域级别 例如
12.17.230.48|12.178.230.63|US|Texas|Temple
12.178.230.64|12.178.230.95|US|Texas|Abilene
12.178.230.96|12.178.230.111|US|Texas|Jayton
12.178.230.112|12.178.230.119|US|Texas|Wichita Falls
12.178.230.120|12.178.230.127|US|Texas|Mansfield
12.178.230.128|12.178.230.159|US|Texas|Waco (Bellmead)
12.178.230.160|12.178.230.167|US|Texas|Irving
12.178.230.168|12.178.230.175|US|Texas|Fort Worth
12.178.230.176|12.178.230.183|US|Texas|Alvarado
12.178.230.184|12.178.230.191|US|Texas|Weatherford
12.178.230.192|12.178.230.199|US|Texas|Haltom City
12.178.230.200|12.178.230.207|US|Texas|Fort Worth (Diamond Hill - Jarvis)
12.178.230.208|12.178.230.223|US|Texas|Fort Worth
12.178.230.224|12.178.230.231|US|Texas|Coppell
12.178.230.232|12.178.230.239|US|Texas|Lubbock
这里所有的都去德州所以我想像这样把所有这些块合并成一个
start_ip_of_first_range|end_ip_of_last_range_of_same_region|US|Texas
虽然我尝试过,但看起来我什至违反了 IPv4 地址基本规则
请推荐任何公式?
好吧,您只需要确定 'supernet' 的最低和最高 IP 子网即可。
12.178.230.48|12.178.230.63|US|Texas|Temple
12.178.230.232|12.178.230.239|US|Texas|Lubbock
因此,要将它们分组,您需要找到包含这些范围的子网掩码。您可以使用的唯一子网掩码是 /24。 /25 只会为您提供范围从 12.178.230.0-12.178.230.127
或 12.178.230.128-12.178.230.255
.
A /24 子网掩码为您提供以下范围:12.178.230.0-12.178.230.255
Extra: supernet might not be the correct naming convention, but it gives you a general idea that this is the global IP range for all your results.
好吧,写到这里已经晚了,但是我找到了一个简单而冗长的方法来实现这个objective。
1. First convert all the ranges in the form of network_address|subnet_mask
2. sort whole the file in descending IP address
3. Now check if two lines fulfill following conditions
a. Same subnet mast &&
b. Re-Check network IP if the position of first set bit from right is greater than host bit length &&
c. Network IP of the line = network ip of next line + 2^(number of host bit) +1 &&
d. First set bit from right in first line should be equal and less than the first set bit in next line's IP. &&
e. Both line should have same location &&
4. In that case remove the next line and decrease the subnet mask length by one.
5. Now the resultant range will serve exactly same IP addresses as much the initial two ranges were serving neither more or less .
6. To make more merging keep repeating step 2 to 5
我使用 C 程序和 bash 实用程序完成了这项工作。虽然我没有在这里粘贴程序如果有人需要它我会尽量把确切的解决方案放在这里。
这可能是著名问题的解决方案 http://www.perlmonks.org/?node_id=118346