用于文件信息的 AIX 脚本
AIX script for file information
我在 AIX 服务器中有一个文件，其中包含以下格式的多个记录条目
Name(ABC XYZ) Gender(Male)
AGE(26) BDay(1990-12-09)
我的问题是我想从文件中提取所有记录的姓名和生日。我想像下面这样列出它：
ABC XYZ 1990-12-09
有人可以帮我编写脚本吗
可能是这样的：
awk -F"[()]" '/Name/ && /Gender/{name=} /BDay/{print name,}' file.txt
也就是说... "treat opening and closing parentheses as field separators. If you see a line go by that contains Name and Gender, save the second field in the variable name. If you see a line go by that contains the word Bday, print out the last name you saw and also the fourth field on the current line."
我在 AIX 服务器中有一个文件，其中包含以下格式的多个记录条目
Name(ABC XYZ) Gender(Male)
AGE(26) BDay(1990-12-09)
我的问题是我想从文件中提取所有记录的姓名和生日。我想像下面这样列出它：
ABC XYZ 1990-12-09
有人可以帮我编写脚本吗
可能是这样的：
awk -F"[()]" '/Name/ && /Gender/{name=} /BDay/{print name,}' file.txt
也就是说... "treat opening and closing parentheses as field separators. If you see a line go by that contains Name and Gender, save the second field in the variable name. If you see a line go by that contains the word Bday, print out the last name you saw and also the fourth field on the current line."