C++ 创建书店，语法错误

Question

我收到的错误是 C3867 'Member::getMN': non-standard syntax; use '&' to create a pointer to member'。 getID、nBks、cost 和 tcost 的相同错误。

询问客户的姓氏和身份证号码，然后是他们想要的书的数量，并询问这本书的费用。必须显示所有信息。不确定我的错误到底在哪里。

#ifndef MEMBER_H
#define MEMBER_H
#include <string>
#include <iostream>

using namespace std;

// define the class members and member function prototypes here
class Member 
{
private:
    string MemberName;//customer name
    string MemberID;//customer id
    int numBooks=0;//number of books
    double PurchaseAmt=0;//cost of books

public:
    void setMN(string);
    void setmID(string);
    void setnBks(int);
    void setcost(double);
    string getMN() const;
    string getID()const;
    int nBks()const;
    double cost()const;//cost of a book
    double tcost()const;
};
#endif

#include "member.h"   // Needed for the member class
#include <iostream>      // Needed for cout
#include <cstdlib>       // Needed for the exit function
using namespace std;

void Member::setMN(string name)//string size for membername
{   if (name.size() < 12)
        MemberName = name.substr(0, 12);
    else
    {
        cout << "Invalid Member ID\n";
        system("pause");
        exit(EXIT_FAILURE);
    }
}

void Member::setmID(string ID)//string size for MemberID
{   if (ID.size() < 5)
        MemberID = ID.substr(0,5);
    else
    {
        cout << "Invalid Member ID\n";
        system("pause");
        exit(EXIT_FAILURE);
    }

}
void Member::setnBks(int num)//check for number of books
{   if (num > 0)
        numBooks = num;
    else
    {
        cout << "Invalid book count, must be over 0.\n";
        system("pause");
        exit(EXIT_FAILURE);
    }
}

void Member::setcost(double amount)//check for cost of the book.
{   if (amount > 0)
        PurchaseAmt = amount;
    else
    {
        cout << "Invalid cost, can not be less then 0.\n";
        system("pause");
        exit(EXIT_FAILURE);
    }
}


string Member::getMN() const
{   return MemberName;
}

string Member::getID() const
{   return MemberID;
}

int Member::nBks() const
{   return numBooks;
}

double Member::cost() const
{   return PurchaseAmt;
}

double Member::tcost() const//getting the total cost of the book(s)
{   return numBooks * numBooks;

}

#include <iostream>
#include <string>
#include <iomanip>
#include "member.h"  // Needed for Member class

using namespace std;

void getinfo(Member&);
void display(Member);

int main()
{
    Member books;

    system("pause");
    return 0;
} // end main

//this function returns member name and id, also number of books and the cost.
  // this function displays the book store's data.
void getinfo(Member& x)
{
    string MemberName, MemberID;
    int numBooks;
    double PurchaseAmt;

    cout << fixed << showpoint << setprecision(2);

    cout << "What is the members last name, must be under 12 char?\n";
    cin >> MemberName;
    x.setMN(MemberName);

    cout << "What is the members ID, must be under 5 int?\n";
    cin >> MemberID;
    x.setmID(MemberID);

    cout << "How many books?\n";
    cin >> numBooks;
    x.setnBks(numBooks);

    cout << "How much does each book cost?\n";
    cin >> PurchaseAmt;
    x.setcost(PurchaseAmt);

} // end getting information.

void display(Member x)
{
    cout << fixed << showpoint << setprecision(2);
    cout << "The member's last name is : " << x.getMN << endl;
    cout << "The member's ID is : " << x.getID << endl;
    cout << "The number of books bought are : " << x.nBks << endl;
    cout << "The cost per book is : " << x.cost << endl;
    cout << "The total is : " << x.tcost << endl;

}

Answer 1

你只是忘记了方法名后面的()

void display(Member x)
{
  cout << fixed << showpoint << setprecision(2);
  cout << "The member's last name is : " << x.getMN() << endl;
  cout << "The member's ID is : " << x.getID() << endl;
  cout << "The number of books bought are : " << x.nBks() << endl;
  cout << "The cost per book is : " << x.cost() << endl;
  cout << "The total is : " << x.tcost() << endl;

}

C++ 创建书店，语法错误

C++ Creating a Book store, syntax error

c++

string

pointers

syntax-error

purchase-order