如何将一个长字符串按单词拆分为 2 个字符串，但不在单词中间[java]

Question

如果我的字符串太长，我想把它分成2个子字符串显示。

这是我使用的代码：

if(newQuestion.length() > 35){
            String first_part = newQuestion.substring(0,newQuestion.length()/2);
            String second_part = newQuestion.substring(newQuestion.length()/2);
            question1.setText(first_part + "\n" + second_part);
        }
        else{question1.setText(newQuestion + "");}

这导致：

Bronze age settlemen

ts in northern India.

如果字符串总长度 > 35，但不拆分实际单词，我该如何拆分它，因为它不好？

Answer 1

分裂于 space。然后将单词添加到第一个字符串，直到字符串长度为 35 个字符，然后将其余单词添加到 2. 字符串。但听起来视图 question1 应该能够自己处理这个问题？

    String newQuestion = "Bronze age settlements in northern India.";
    String[] words = newQuestion.split(" ");
    String line1 = "";
    String line2 = "";
    int size = 0;
    for(int i = 0; (line1.length() + words[i].length()) < 25; i++) {
        size++;
        line1 += words[i] + " ";
    }
    for(int j = size; j < words.length; j++) {
         line2 += words[j] + " ";
    }
    System.out.println(line1);
    System.out.println(line2);

如何将一个长字符串按单词拆分为 2 个字符串，但不在单词中间[java]

How to split a long string in 2 strings by words, but not in the middle of a word[java]

string

stringtokenizer