如何制作一个 8 位二进制计算器

Question

所以我做了一个 8 位二进制计算器，但我有点用下面的方法作弊了。

  public static int[] convertToBinary(int b){
    String toStr = Integer.toBinaryString(b);
    String fStr = ("00000000"+toStr).substring(toStr.length());
    String[] array = fStr.split("");
    int[] finalArray = new int[array.length-1]; 
    for(int i = 0; i < finalArray.length; i++){
      finalArray[i] = Integer.parseInt(array[i+1]);
    }

    return finalArray;
  }


  public static int[] addBin(int a[], int b[]){
    int[] added = new int[a.length];
    for(int i = added.length - 1; i >= 0; i--){
      if((a[i]+b[i] > 1)){
        System.out.println("Error: overflow");
        break;
      }else{
        added[i] = (a[i]+b[i]);
      }
    }
    return added;
  }

我的问题是如何将整数转换为二进制数以及如何将两个二进制数相加。

Answer 1

这是您要找的吗？

public static int[] convertToBinary(int b) {
  if (b < 0 || b > 255) {
    throw new IllegalArgumentException("Argument must be between 0 and 255");
  }
  int[] result = new int[8];
  // Working from the right side of the array to the left, we store the bits.
  for (int i = 7; i >= 0; i--) {
    result[i] = b & 1; // Same as b % 2
    b >>>= 1; // Same as b /= 2
  }
  return result;
}


public static int[] addBin(int[] a, int[] b) {
  if (a.length != 8 || b.length != 8) {
    throw new IllegalArgumentException("Arguments must be octets");
  }
  for (int i = 0; i < 8; i++) {
    if (a[i] < 0 || a[i] > 1 || b[i] < 0 || b[i] > 1) {
      throw new IllegalArgumentException("Arguments must be binary");
    }
  }
  // Working from the right side of the array to the left, we find the sum.
  int[] result = new int[8];
  for (int i = 7; i >= 1; i--) {
    int sum = result[i] + a[i] + b[i]; // result[i] holds the carry from the last addition.
    result[i] = sum & 1; // Same as sum % 2
    result[i - 1] = sum >>> 1; // Same as sum / 2. This is the carry.
  }
  // The highest-order bit (bit 0) is handled as a special case to detect overflow.
  int sum = result[0] + a[0] + b[0];
  result[0] = sum & 1;
  if (sum >>> 1 > 0) {
    throw new IllegalArgumentException("Overflow");
  }
  return result;
}

如何制作一个 8 位二进制计算器

How to make an 8 bit Binary Calculator

java

binary

calculator

base

8-bit