获取第 1000 个点的用户（SQL 查询）

Question

我正在尝试做一个查询，以说明来自 school_id 1 的哪个学生获得了第 1000 分 - 在本例中是 'Sharon'

+++++++++++++++++++++++++++++++++++++
# id # school_id # student # points #
#  1 #     1     #  Harry  #   100  #
#  2 #     1     #  Bob    #   200  #
#  3 #     1     #  Jamie  #   150  #
#  4 #     1     #  Lee    #   200  #
#  5 #     1     #  John   #   200  #
#  6 #     1     #  Sharon #   170  #
#  7 #     2     #   Tim   #  2000  #
+++++++++++++++++++++++++++++++++++++

我遇到了以下查询问题，但它return 不是我所期望的：

SELECT
  SUM(points) as pointSum, student
FROM testing
GROUP BY school_id;

我希望得到这样的结果...

++++++++++++++++++++++++++++++++++++++++
# id # school_id # student # pointsSum #
#  6 #     1     #  Sharon #   1020    #
++++++++++++++++++++++++++++++++++++++++

Answer 1

使用派生的 table 计算用户和之前用户（id-wise）的 SUM 点数。

select name, sumpoints
from 
(
select id, name, (select sum(points) from tablename t2
                  where t2.id <= t1.id) sumpoints AND t2.school_id = 1
from tablename t1
) dt
where sumpoints >= 1000
order by id
limit 1

获取第 1000 个点的用户（SQL 查询）

Get the user with the 1000th point (SQL query)

mysql

sql

select-query