C# 对象的前缀和命名空间
Prefixes and Namespaces with C# Objects
我正在尝试创建一个 POST 函数,将 C# class 对象序列化为 XML。
我遇到很大困难的部分是向子根元素的子元素添加名称空间前缀,因此在这种情况下,仅 contact
个子元素。
我似乎能够将前缀添加到 contact
的子元素上的唯一方法是通过 SerializerNamespace
class 添加它们,但是我只能将其添加到附加到根元素,CreateContact
.
我怎样才能做到这一点?
XML 目前出品:
<?xml version=\"1.0\"?>
<CreateContact xmlns:a="http://foo.co.uk/Contact" xmlns="http://foo.co.uk">
<a:contact>
<a:Email>stest@gmail.com</a:Email>
<a:FirstName>Simon</a:FirstName>
<a:LastName>Test</a:LastName>
<a:Phone>09088408501</a:Phone>
<a:Title>Mr</a:Title>
</a:contact>
</CreateContact>
序列化函数:
public static void CreateContact(Contact contact)
{
string tmp = url;
string xml = "";
string result = "";
XmlDocument xd = new XmlDocument();
var cc = new CreateContact();
cc.contact = contact;
var xs = new XmlSerializer(cc.GetType());
XmlSerializerNamespaces xsn = new XmlSerializerNamespaces();
xsn.Add("a", "http://foo.co.uk/Contact");
using (MemoryStream ms = new MemoryStream())
{
xs.Serialize(ms, cc, xsn);
ms.Position = 0;
xd.Load(ms);
xml = xd.InnerXml;
}
using (WebClient web = new WebClient())
{
web.Credentials = new NetworkCredential(username, password);
web.Headers.Add("Content-Type", "application/xml");
try
{
result = web.UploadString(tmp, "POST", xml);
}
catch (WebException ex)
{
}
}
}
XML Class 构造:
[Serializable()]
[XmlRoot(ElementName = "CreateContact", Namespace = "http://foo.co.uk")]
public class CreateContact
{
[XmlElement(ElementName = "contact", Namespace = "http://foo.co.uk/Contact")]
public Contact contact { get; set; }
}
[DataContract(Name = "Contact", Namespace = "http://foo.co.uk/Contact")]
[XmlType("a")]
public class Contact
{
[XmlElement(ElementName = "Email", Namespace = "http://foo.co.uk/Contact")]
[DataMember(Name = "Email")]
public string Email { get; set; }
[XmlElement(ElementName = "FirstName", Namespace = "http://foo.co.uk/Contact")]
[DataMember(Name = "FirstName")]
public string Firstname { get; set; }
[XmlElement(ElementName = "LastName", Namespace = "http://foo.co.uk/Contact")]
[DataMember(Name = "LastName")]
public string Lastname { get; set; }
[XmlElement(ElementName = "Phone", Namespace = "http://foo.co.uk/Contact")]
[DataMember(Name = "Phone")]
public string Phone { get; set; }
[XmlElement(ElementName = "Title", Namespace = "http://foo.co.uk/Contact")]
[DataMember(Name = "Title")]
public string Title { get; set; }
}
XML 期望:
<?xml version=\"1.0\"?>
<CreateContact xmlns="http://foo.co.uk">
<contact xmlns:a="http://foo.co.uk/Contact">
<a:Email>stest@gmail.com</a:Email>
<a:FirstName>Simon</a:FirstName>
<a:LastName>Test</a:LastName>
<a:Phone>09088408501</a:Phone>
<a:Title>Mr</a:Title>
</contact>
</CreateContact>
正如评论中提到的,不同的原因是 contact
应该在命名空间 http://foo.co.uk
中,而不是 http://foo.co.uk/Contact
.
顺便说一句,一些进一步的评论:
- 你可能不需要
DataMember
属性,除非你在其他地方使用DataContractSerializer
。 - 大多数
Xml*
属性在这里都是多余的,可以通过继承XmlRoot
. 来删除或合并
- 如果你只需要 XML 字符串,你最好序列化为
StringWriter
之类的东西而不是流,然后加载到 DOM 中获取文本(如果您需要 XML 声明来指定utf-8
,请参阅 this question)
因此,您将得到如下 XML:
var xsn = new XmlSerializerNamespaces();
xsn.Add("a", "http://foo.co.uk/Contact");
var xs = new XmlSerializer(typeof(CreateContact));
using (var stringWriter = new StringWriter())
{
xs.Serialize(stringWriter, cc, xsn);
xml = stringWriter.ToString();
}
您的 类 定义为:
[XmlRoot(ElementName = "CreateContact", Namespace = "http://foo.co.uk")]
public class CreateContact
{
[XmlElement(ElementName = "contact")]
public Contact Contact { get; set; }
}
[XmlRoot("contact", Namespace = "http://foo.co.uk/Contact")]
public class Contact
{
public string Email { get; set; }
public string FirstName { get; set; }
public string LastName { get; set; }
public string Phone { get; set; }
public string Title { get; set; }
}
有关完整示例,请参阅 this fiddle。