如何以更"elegant"的方式重写这行代码？

Question

所以我有这行代码，我正试图找到一种更优雅的方式来编写它们：

         int randomHints1 = hintsRandom.nextInt(1200-100) + 100;
         int randomHints2 = hintsRandom.nextInt(1200-100) + 100;
         int randomHints3 = hintsRandom.nextInt(1200-100) + 100;
         int randomHints4 = hintsRandom.nextInt(1200-100) + 100;
         int randomHints5 = hintsRandom.nextInt(1200-100) + 100;
         int randomHints6 = hintsRandom.nextInt(1200-100) + 100;
         int randomHints7 = hintsRandom.nextInt(1200-100) + 100;
         int randomHints8 = hintsRandom.nextInt(1200-100) + 100;
         int randomHints9 = hintsRandom.nextInt(1200-100) + 100;
         int randomHints10 = hintsRandom.nextInt(1200-100) + 100;

我猜 "for loop" 方法会是答案，但我找不到解决这个问题的方法。非常感谢你们。

Answer 1

int[] randomHints = new int[10];
for(int i=0;i<randomHints.length;i++)
    randomHints[i] = hintsRandom.nextInt(1100) + 100;

Answer 2

利用数组

int[] randomHints = new int[10];
for (int i = 0; i < randomHints.length; i++) {
    randomHints[i] = hintsRandom.nextInt(1200 - 100) + 100;
}

Answer 3

如果使用数组会更优雅:

int[] randomHints = new int[10];
...
for(int i = 0;i<randomHints.length;i++) {
    randomHints[i] = hintsRandom.nextInt(1200-100) + 100;
}

ps.: 如果你需要动态数量的随机数，你可以使用数组列表

Answer 4

我的回答和别人基本一样，都是用数组和迭代，但是我是用Java8个流写在一行里的。我觉得这样更优雅。

int[] randomHints = new int[10];
Arrays.stream(randomHints).forEach(i -> randomHints[i] = hintsRandom.nextInt(1200 - 100) + 100);

Answer 5

int[] randomHints = IntStream.generate(() -> 100 + hitsRandom.nextInt(1100)).limit(10).toArray();

如何以更"elegant"的方式重写这行代码？

How to rewrite this lines of code in a more "elegant" way?

java

for-loop

int