Google 地理编码 Json C# 中的解析问题

Question

我的代码工作正常，但我似乎无法到达树的更深部分。我正在尝试拉经度和纬度。下面的代码将 'status' 拉为“OK”没问题（在响应的最后）。'geometry' -> 'location' -> 'lat' 的语法是什么'lng'?

这是我的代码：

string RawAddress = "163 Leektown Road, New Gretna, NJ 08004";
string Address = RawAddress.Replace(" ", "+");
string AddressURL = "http://maps.google.com/maps/api/geocode/json?address=" + Address;
var result = new System.Net.WebClient().DownloadString(AddressURL);
dynamic data = JObject.Parse(result);

Lat.Text = data.status;

这是 API 生成的内容：

{
   "results" : [
  {
     "address_components" : [
        {
           "long_name" : "Mountain View",
           "short_name" : "Mountain View",
           "types" : [ "locality", "political" ]
        },
        {
           "long_name" : "Santa Clara County",
           "short_name" : "Santa Clara County",
           "types" : [ "administrative_area_level_2", "political" ]
        },
        {
           "long_name" : "California",
           "short_name" : "CA",
           "types" : [ "administrative_area_level_1", "political" ]
        },
        {
           "long_name" : "United States",
           "short_name" : "US",
           "types" : [ "country", "political" ]
        }
     ],
     "formatted_address" : "Mountain View, CA, USA",
     "geometry" : {
        "bounds" : {
           "northeast" : {
              "lat" : 37.4508789,
              "lng" : -122.0446721
           },
           "southwest" : {
              "lat" : 37.3567599,
              "lng" : -122.1178619
           }
        },
        "location" : {
           "lat" : 37.3860517,
           "lng" : -122.0838511
        },
        "location_type" : "APPROXIMATE",
        "viewport" : {
           "northeast" : {
              "lat" : 37.4508789,
              "lng" : -122.0446721
           },
           "southwest" : {
              "lat" : 37.3567599,
              "lng" : -122.1178619
           }
        }
     },
     "partial_match" : true,
     "types" : [ "locality", "political" ]
  }
  ],
  "status" : "OK"
  }

Answer 1

以下是获得所需内容的步骤：

Post 你的 JSON 在 http://json2csharp.com/。取结果类并合并重复项，你会得到：

public class AddressComponent
{
    public string long_name { get; set; }
    public string short_name { get; set; }
    public List<string> types { get; set; }
}

public class Bounds
{
    public Location northeast { get; set; }
    public Location southwest { get; set; }
}

public class Location
{
    public double lat { get; set; }
    public double lng { get; set; }
}

public class Geometry
{
    public Bounds bounds { get; set; }
    public Location location { get; set; }
    public string location_type { get; set; }
    public Bounds viewport { get; set; }
}

public class Result
{
    public List<AddressComponent> address_components { get; set; }
    public string formatted_address { get; set; }
    public Geometry geometry { get; set; }
    public bool partial_match { get; set; }
    public List<string> types { get; set; }
}

public class RootObject
{
    public List<Result> results { get; set; }
    public string status { get; set; }
}

（您也可以使用 Paste JSON as Classes or https://jsonutils.com/ 来生成您的初始类型定义。）

用 Json.NET 反序列化你的 JSON 像这样：

    var root = JsonConvert.DeserializeObject<RootObject>(result);

您的查询返回了多个结果，因此您需要像这样遍历返回的位置：

    foreach (var singleResult in root.results)
    {
        var location = singleResult.geometry.location;
        var latitude = location.lat;
        var longitude = location.lng;
        // Do whatever you want with them.
    }

Answer 2

'geometry' -> 'location' -> 'lat' 和 'lng' 的语法是：

JObject data = JObject.Parse(result);

string lat = (string)data["results"][0]["geometry"]["location"]["lat"];
string lng = (string)data["results"][0]["geometry"]["location"]["lng"];

Google 地理编码 Json C# 中的解析问题

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