Hibernate Envers：@Audited 子类

Question

我有实体 Parent 和 Child 的 classic 继承持久性，其中 Child 扩展父级。 Class Parent 是抽象的，而 Child 不是。

我想审计子。这个实体在我的控制之下，而父不是。此外，它还有许多其他子class项不需要审计。整个层级的继承策略是JOINED.

所以我用 @Audited 和 @AuditOverride(forClass 注释了 Child = Parent.class).

我得到的是这个错误：

"org.hibernate.MappingException: Entity 'Child' is audited, but its superclass: 'Parent' is not."

对了，我用的是envers 4.0.1.Final版本。

有人知道我该怎么做吗？ 我试过在 Child class 中删除 @Audited，删除 @AuditOverride，使用在 @Audited 注释中弃用了 auditParents，但似乎没有任何效果。

这是父实体：

@Entity
@Table(name = "parent")
@Inheritance(strategy = InheritanceType.JOINED)
@DiscriminatorColumn(name = "type")
public class Parent {
    public Parent() {
        super();
    }

    @Id
    @GeneratedValue(strategy = IDENTITY)
    @Column(name = "base_id", unique = true, nullable = false)
    private Integer baseId;

    @Column(name = "base_field")
    private String baseField;

    @Column(name = "type")
    private String type;

    // getters and setters
}

这是我的子实体：

@Entity
@Table(name = "child")
@DiscriminatorValue("CHILD")
@Audited
@AuditOverride(forClass = Parent.class)
public class Child extends Parent {
    public Child() {
        super();
    }

    @Column(name = "child_field")
    private String childField;

    // getters and setters
}

这是实体：

CREATE  TABLE `REVINFO` (
  `REV` BIGINT NOT NULL AUTO_INCREMENT,
  `REVTSTMP` BIGINT NULL ,
  PRIMARY KEY (`REV`)
);

CREATE TABLE `parent` (
  `base_id` int(11) NOT NULL AUTO_INCREMENT,
  `base_field` varchar(45) DEFAULT NULL,
  `type` varchar(45) NOT NULL,
  PRIMARY KEY (`base_id`)
);

CREATE TABLE `child` (
  `base_id` int(11) NOT NULL AUTO_INCREMENT,
  `child_field` varchar(45) DEFAULT NULL,
  PRIMARY KEY (`base_id`)
);

CREATE TABLE `child_AUD` (
  `base_id` int(11) NOT NULL,
  `REV` BIGINT NOT NULL,
  `REVTYPE` tinyint(2) DEFAULT NULL,
  `child_field` varchar(45) DEFAULT NULL,
  PRIMARY KEY (`base_id`,`REV`)
);

这是一个测试用例：

public class EnversInheritanceTest extends AbstractJUnit4SpringContextTests {

    @Inject
    private EntityManagerFactory entityManagerFactory;

    private EntityManager entityManager;

    @Test
    public void inheritanceTest() {

        this.entityManager = this.entityManagerFactory.createEntityManager();

        Child child = this.createChild();
        this.saveChild(child);

        this.modifyChild(child);
        this.saveChild(child);

        Assert.assertNotNull(child.getBaseId());
        Assert.assertNotNull(this.getOriginalRevision(child.getBaseId()));

        Child original = this.getOriginalChild(child.getBaseId());

        Assert.assertNotNull(original);
        Assert.assertEquals("child", original.getChildField());

    }

    private Child createChild() {
        Child child = new Child();
        child.setBaseField("base");
        child.setChildField("child");
        child.setType("CHILD");
        return child;
    }

    private void saveChild(Child child) {
        this.entityManager.getTransaction().begin();
        this.entityManager.persist(child);
        // We need to commit in order to trigger Envers magic
        this.entityManager.getTransaction().commit();
    }

    private void modifyChild(Child child) {
        child.setBaseField("foo");
        child.setChildField("bar");
    }

    public Child getOriginalChild(Serializable id) {
        Object queryResult = this.getAuditReader().createQuery()
                .forEntitiesAtRevision(Child.class, this.getOriginalRevision(id))
                .add(AuditEntity.id().eq(id))
                .getSingleResult();
        return (Child) queryResult;
    }

    private Number getOriginalRevision(Serializable id) {
        AuditProjection minRevNumberAuditProjection = AuditEntity.revisionNumber().min();
        Number revision = (Number) this.getAuditReader().createQuery()
                .forRevisionsOfEntity(Child.class, false, false)
                .add(AuditEntity.id().eq(id))
                .addProjection(minRevNumberAuditProjection)
                .getSingleResult();

        return revision;
    }

    private AuditReader getAuditReader() {
        return AuditReaderFactory.get(this.entityManager);
    }

}

提前致谢！

Answer 1

一个很好的问题。有 same discussion on the jboss developers forum in 2013 year. And the answer was from the founder and project lead of Hibernate Enver:

You would have to get the superclass audited somehow. Currently there's no other way to specify such metadata except for annotations.

在同一个讨论树中，根据父class也应该被注释的事实，建议在运行时注释它们。但是这个决定似乎很难看并且不适合你的情况：你可以手动注释父 class。

作为变通方法，如果您不希望父 class 被审计，您可以尝试创建一个基本摘要 MappedSuperClass，它基本上与 Parent 相同，而 Parent 将只是它的后代，然后尝试为 Child class 再次放置 @AuditOverride。它可能会 "skip" 审核 Parent class 并为 Child.

审核

Answer 2

尝试用@Audited注解标记父子classes 但对于父 class 添加 @Audited(targetAuditMode = NOT_AUDITED)

Hibernate Envers：@Audited 子类

Hibernate Envers: @Audited on a subclass

java

hibernate

hibernate-envers