Drools DSL - 如何在规则中使用括号

Question

Drools 版本：6.3.0.Final

波乔：

public class Person {
    private Integer age;
    private Integer childrens;
    private String name;
    private String address;
    (...) 
}

DSL 文件：

[condition][]and=&&
[condition][]or=||
[condition][]is less than or equal to=<=
[condition][]is less than=<
[condition][]is greater than or equal to=>=
[condition][]is greater than=>
[condition][]is equal to===
[condition][]There is a [Pp]erson with=$person:Person()
[condition][].{field:\w*}  {operator}  {value:\d*}={field}  {operator}  {value}
(...)

DSRL 文件：

package <package>;

import <import class>.*

global org.slf4j.Logger logger;

expander <class>.dsl;

rule "R1"
    when
        There is a person with
        .age is greater than 10 or .chidldrens is less than 2 and .name is  equal to "<name>"
    then
        (...)
end 

rule "R2"
    when
        There is a person with
        (.age is greater than 10 or .childrens is less than 2) and .name is equal to "<name>"
    then
        (...)
end

DRL（来自 R1）：

(...)
rule "R1"
        when
            $person:Person(age > 10 || childrens < 2 && name = "<name>")
        then
            (...)
    end 
(...)

DRL（来自R2）：没有生成规则。

如果我删除括号，它可以正常工作，但如果有括号，DRL 文件将无法正确生成。所以只有 R2 规则有效，但我的目标是 R1 规则。

有什么想法吗？

Answer 1

应使用以下 DSL 定义：

[condition][]There is a Person with=Person()
[condition][]- :{field:\w*}  {operator}  {value:\d*}=
            {field}  {operator}  {value}
[condition][]:{field:\w*}  {operator}  {value:\d*}=
             {field} {operator} {value}
# operators as in the question

以及数码单反相机：

rule R1
when
There is a Person with
- :call_count is less than 10 or :name is equal to "Joe" 
- :points is greater than 5
then
    ...
end

这导致

rule R1
when
Person(call_count  <  10 || name  ==  "Joe", points  >  5)
then
 ...
end

6.3.0 DSL 扩展器中至少有两个错误。这曾经在 5.5 中有效，但在 DSL 解析中做了一些 "improvement"。您应该在 Drools 错误报告站点上提出一个 JIRA。（但我认为 Drools 团队不会在 DSL 上花费任何时间或精力，在 6.x 开始工作时，DSL 已被降级为继子。

Answer 2

我想我找到了一个可能的解决方案是：

DSL 文件（用这个新条件替换）：

[condition][]There is a [Pp]erson that {constraints}=$person:Person({constraints})
[condition][]{field:\w*}\s+{operator}\s+{value:\s*}={field}  {operator}  {value}

DSRL（从第一行开始定义约束）：

(...)
There is a person that ((age is greater than 10 or chidldrens is less than 2) and name is equal to "<name>")
(...)

DRL（生成）：

(...)
$person:Person((age > 10 || childrens < 2) && name == "name")
(...)

使用这个新的 DSL 定义括号是受支持的，它按预期工作。你怎么看@laune？

Drools DSL - 如何在规则中使用括号

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