sed 在匹配单行字符串后追加多行字符串

sed append multi-line string after matching a single line string

如果可能,我想将 sed 用于此解决方案。这是我的情况:

我有一个多行字符串,将通过外部方式提供给 sed - 可能是人偶 shell exec 或 bash 脚本。字符串看起来像:

$string = 'blah blah blah\nblahblah\nblah blah blah\n\n'

我想要 运行 一个 sed 命令,在找到匹配后追加这个字符串 -

sed -i "/^\[org\/gnome\/login-screen\]/a banner-message-text='$string'" /etc/dconf/db/gdm.d/00-mybanner

问题在于 sed\n 字符解释为换行符。请注意,我意识到我在 sed 命令中声明 $string 变量的方式可能会有所不同,具体取决于它的执行方式,但即使在命令行上手动键入字符串也会产生多行输出。所以文件最终看起来像:

[org/gnome/login-screen]
banner-message-text='blah blah blah
blablah
blah blah blah

'
banner-message-enable=true

这会导致 dconf update 抛出错误。我希望文件看起来像:

[org/gnome/login-screen]
banner-message-text='blah blah blah\nblablah\nblah blah blah\n\n'
banner-message-enable=true

但我似乎无法让 sed 停止自己解释 \n。 谢谢!

编辑 - 使用 Puppet 实现解决方案 (@tom-fenech) 的完整上下文:

  $banner_msg = 'blah blah blah\nblahblah\nblah blah blah\n\n'

  $comply_cmd = "find /etc/dconf/db/gdm.d -maxdepth 1 -type f -print0 | xargs -0 sed -i '/^banner-message-text=/d' || /bin/true && \
    (grep -q \"^\[org/gnome/login-screen\]\" /etc/dconf/db/gdm.d/99-banner && \
    sed -i \"/^\[org\/gnome\/login-screen\]/a banner-message-text='$(printf '%q' \"${banner_msg}\")'\" /etc/dconf/db/gdm.d/99-banner) || \
    (echo -e \"\n\[org/gnome/login-screen]\" >> /etc/dconf/db/gdm.d/99-banner && \
    echo \"banner-message-text='${banner_msg}'\" >> /etc/dconf/db/gdm.d/99-banner)"

  $unless_cmd = "grep -q \"^banner-message-text='$(printf '%q' \"${banner_msg}\")'$\" /etc/dconf/db/gdm.d/99-banner"

  exec { 'gdm-banner-msg':
    path     => '/sbin:/bin:/usr/sbin:/usr/bin',
    umask    => '022',
    provider => shell,
    command  => $comply_cmd,
    unless   => $unless_cmd,
    notify   => Exec['dconf-update'],
  }

谢谢大家!

您需要转义反斜杠:

$ string='blah blah blah\nblahblah\nblah blah blah\n\n'
$ echo $string
blah blah blah\nblahblah\nblah blah blah\n\n
$ cat foo.txt
foo
baz
test

$ sed -i "/^foo/a bar='$string'" foo.txt 
$ cat foo.txt 
foo
bar='blah blah blah\nblahblah\nblah blah blah\n\n'
baz
test

$

使用 printf%q 格式说明符。这会为您处理转义:

$ echo "$string"
blah blah blah\nblahblah\nblah blah blah\n\n
$ printf '%q' "$string"
blah\ blah\ blah\nblahblah\nblah\ blah\ blah\n\n

来自man bash

%q causes printf to output the corresponding argument in a format that can be reused as shell input.

这意味着空格也被反斜杠转义了,但这没有坏处。

正在测试:

$ cat file
[org/gnome/login-screen]
$ sed "/^\[org\/gnome\/login-screen\]/a banner-message-text='$(printf '%q' "$string")'" file
[org/gnome/login-screen]
banner-message-text='blah blah blah\nblahblah\nblah blah blah\n\n'

准备初始配置文件:

echo -e "[org/gnome/login-screen]\nbanner-message-enable=true"> /etc/dconf/db/gdm.d/00-mybanner
cat /etc/dconf/db/gdm.d/00-mybanner

[org/gnome/login-screen]
banner-message-enable=true

插入新横幅消息而不解释 \n 字符:

string='blah blah blah\nblahblah\nblah blah blah\n\n'; sed -i "/^\[org\/gnome\/login-screen\]/a banner-message-text=\'$string\'" /etc/dconf/db/gdm.d/00-mybanner

查看结果:

cat /etc/dconf/db/gdm.d/00-mybanner

[org/gnome/login-screen]
banner-message-text='blah blah blah\nblahblah\nblah blah blah\n\n'
banner-message-enable=true

要点是:在字符串中的每个 \n 前添加一个 斜线。这将阻止 sed 解释 \n 字符。