如何让 Yii2 处理数据提供者的两个不同实例？

Question

这是站点控制器index.php。在这里，我想在同一个 page.But 上显示来自不同 table 的两个列表，它只显示两个 div.when 的一个 table 数据我只在两个 div 上设置 $dataProvider小部件，如果我设置在 actionIndex() 中创建的 $dataProvider2，它会收到错误 $dataProvider2 not found.

                        <?= GridView::widget([
                        'dataProvider' => $dataProvider,
                        'columns' => [
                            ['class' => 'yii\grid\SerialColumn'],
                       [

                           'attribute'=>'practiceCode',
                           'format' => 'raw',
                           'value'=>function ($model, $index, $widget) {
                       },
                    ],
                    'firstName',

                        ],

              ]); ?>

            </div>
            <div class="col-lg-6" style="border:solid 1px;">
                <h2>Member</h2>
                <?= GridView::widget([
                        'dataProvider2' => $dataProvider2,//Error $dataProvider2 not found
                        'columns' => [
                            ['class' => 'yii\grid\SerialColumn'],
                       [

                           'attribute'=>'memberCode',
                           'format' => 'raw',
                           'value'=>function ($model, $index, $widget) {

                       },
                    ],
                    'firstName',
              ]); ?>    
            </div>

这是 actionIndex() 这里我写了两个 dataProvider($dataProvider,$dataProvider2) 但是我无法在 index.php widget

中设置这个 dataProvider

public function actionIndex()
    {
        $query = new \yii\db\Query;
        $query->select('*')
              ->from('practice');
        $query->createCommand();

        $dataProvider = new ActiveDataProvider([
            'query' => $query,
            'pagination' => [
            'pageSize' => 10,
             ],
        ]);
        $query = new \yii\db\Query;
        $query->select('*')
              ->from('member');
        $query->createCommand();

        $dataProvider2 = new ActiveDataProvider([
            'query' => $query,
            'pagination' => [
            'pageSize' => 10,
             ],
]);
        return $this->render('index', [
            'dataProvider' => $dataProvider,'dataprovider2'=>$dataProvider2 ]);
}

Answer 1

您需要将 dataProvider2 更改为 dataProvider

<div class="col-lg-6" style="border:solid 1px;">
<h2>Member</h2>
<?= GridView::widget([
    'dataProvider' => $dataProvider2,//Error $dataProvider2 not found
    'columns' => [
        ['class' => 'yii\grid\SerialColumn'],
        [

            'attribute'=>'memberCode',
            'format' => 'raw',
            'value'=>function ($model, $index, $widget) {

            },
        ],
        'firstName',
    ]
]); ?>

因为 dataProvider 是一个属性的 GridView .. 它会起作用

并将您的控制器操作更改为

return $this->render('index', [
        'dataProvider' => $dataProvider,'dataProvider2'=>$dataProvider2 ]);

如何让 Yii2 处理数据提供者的两个不同实例？

How to make Yii2 handle two different instances of a dataprovider?

php

widget

yii2

dataprovider