在字符串数组中查找下一个可用日期

Find next available day in an Array of string

我一直在尝试找出如何根据当前日期获取下一个可用日期,即,如果今天是星期五,则在数组中搜索下一个最近的日期,例如如果数组值为 1[Monday], 2 [星期二], 4[星期四], 6[星期六] 那我第二天应该是星期六

这是我试过的

    //Here i'll get days like 0, 2, 3, 4, 6 pattern, and i'm spliting them based on comma to get single-single day value in array of string 
string[] GetDays = DayInWeek.Split(','); [Here day patterns will change everytime, based on user selection]

//Here i'm looping to take each day and get Enum Text based on Enum Value
foreach (string FirstDay in GetDays)
{ 
    //Here i'm converting the string value into int and passing to DayOfWeek Enum to get respective day
    DayOfWeek DayChoosen = ((DayOfWeek)(Convert.ToInt32(FirstDay)));

    //Here i have my actual day for example Friday
    DayOfWeek StartDay = "Friday";

    //Here i need condition to find next available day in the foreach i.e., after Friday next value should be Saturday, or Sunday, Monday & so on until Friday==Friday
    if (StartDay == DayChoosen)
    {
        //End foreach
    }
}

正如我所说的,根据现在的日期,我应该找到下一个可用的日期,即,如果星期五,我应该搜索星期六,如果星期六不存在,那么星期日、星期一等等,直到星期五=星期五

试试这个;

    //Here i'll get days like 0, 2, 3, 4, 6 pattern, and i'm splitting them based on comma to get single-single day value in array of string 
    string DayInWeek = "0, 2, 3, 4, 6";
    string[] GetDays = DayInWeek.Split(','); //[Here day patterns will change everytime, based on user selection]

    DayOfWeek nextAvailableDay;

    //Here i'm looping to take each day and get Enum Text based on Enum Value
    foreach (string FirstDay in GetDays)
    {
        //Here i'm converting the string value into int and passing to DayOfWeek Enum to get respective day
        DayOfWeek DayChoosen = ((DayOfWeek)(Convert.ToInt32(FirstDay)));

        //Here i have my actual day for example Friday
        DayOfWeek StartDay = DayOfWeek.Friday;

        //Here i need condition to find next available day in the foreach i.e., after Friday next value should be Saturday, or Sunday, Monday & so on until Friday==Friday
        if (StartDay.Equals(DayChoosen))
                        break;

        if (StartDay < DayChoosen)
        {
            nextAvailableDay = DayChoosen;
            break;
        }
        continue;
    }

foreach 不需要所有这些操作。

您可以执行以下操作:

private int nextDay(string dayInWeek, int startDay) 
{
    int[] getDays = dayInWeek.Split(',').Select(int.Parse).ToArray();   

    return getDays.Where(d => d > startDay).Any()
        ? getDays.Where(d => d > startDay).Min()
        : getDays.Min();
}

此算法检查是否有一周中的任何几天出现在您的数组中,并且出现在 startDay 之后。否则,它输出一周中的第一个可用日期。

例如,对于字符串“0, 2, 3, 4, 6”:

  • for startDay 0 - 输出 2,因为它是大于 0
  • 的最小整数
  • 对于 startDay 1 - 输出 2
  • 对于 startDay 3 - 输出 4
  • for startDay 6 它没有找到超过 6 的项目,并输出最小值 0

对于字符串“5”(仅限星期五):

  • for startDay 5, 6 - 没有找到超过 5 的项目,输出最小值 (5)
  • for startDay 0-4 - 输出 5,作为大于 0-4
  • 的最小数

你应该在 int 名单上玩。我给你伪代码。

算法:

  1. 对可用列表进行排序
  2. 从列表中获取所有更大的数字(大于你当前的数字)
    1. select现在最小,突破
  3. 如果您没有更大的数字,select所有最小数字(小于您当前的数字)
    1. select 现在这个列表的最大值,然后打破
  4. 如果你没有任何更大或更小的数字,比 select 相同的数字和中断
  5. 现在将数字转换为工作日

这是我想出的解决这个问题的可能算法。您可以将其转换为代码。可能不是最好的,但我相信它会很好用。

检查这个:

Console.WriteLine("Kindly provide input");
            string DayInWeek = Console.ReadLine();
            string[] GetDays = DayInWeek.Split(',');
            Array.Sort(GetDays);
            DateTime dt = DateTime.Today;
            int i = (int)dt.DayOfWeek;
            Console.WriteLine("Today is " + (DayOfWeek)i);
            bool flag = false;
            foreach (string FirstDay in GetDays)
            {
                if (Convert.ToInt32(FirstDay) > i)
                {
                    Console.WriteLine((DayOfWeek)Convert.ToInt32(FirstDay) + " is the next day");
                    flag = true;
                    break;
                }
            }
            if (!flag)
            {
                Console.WriteLine((DayOfWeek)Convert.ToInt32(GetDays[0]) + " is the next day");
            }
            Console.ReadKey();