重构 C 函数以在 O(n) 到 JavaScript 中找到二叉树的直径
Refactoring C function to find diameter of Binary Tree in O(n) to JavaScript
我在 understanding/re-writing "optimized" C 函数 here 中遇到问题,该函数用于查找二叉树的直径。我不明白它是如何跟踪高度的。我知道它使用第二个参数 height 来完成此操作,但在代码中我什至没有看到正在使用的 height 参数。我很难理解 C 中的函数,我主要用 JavaScript 编写。我能够重写页面上的所有其他功能,但没有问题。
/*The second parameter is to store the height of tree.
Initially, we need to pass a pointer to a location with value
as 0. So, function should be used as follows:
int height = 0;
struct node *root = SomeFunctionToMakeTree();
int diameter = diameterOpt(root, &height); */
int diameterOpt(struct node *root, int* height)
{
/* lh --> Height of left subtree
rh --> Height of right subtree */
int lh = 0, rh = 0;
/* ldiameter --> diameter of left subtree
rdiameter --> Diameter of right subtree */
int ldiameter = 0, rdiameter = 0;
if(root == NULL)
{
*height = 0;
return 0; /* diameter is also 0 */
}
/* Get the heights of left and right subtrees in lh and rh
And store the returned values in ldiameter and ldiameter */
ldiameter = diameterOpt(root->left, &lh);
rdiameter = diameterOpt(root->right, &rh);
/* Height of current node is max of heights of left and
right subtrees plus 1*/
*height = max(lh, rh) + 1;
return max(lh + rh + 1, max(ldiameter, rdiameter));
}
近似相当于通过引用传递(在您提供的示例中有很好的评论)将是 属性 的对象:
var heightHolder = { height:0};
var diam = diameterOpt(root, heightHolder);
console.log(heightHolder.height);
function diameterOpt(root, heightHolder){
if (!root) {
heightHolder.height = 0;
return 0;
}
var refLh = {height:0};
var refRh = {height:0};
var ldiameter = diameterOpt(root.left, refLh);
....
heightHolder.height = Math.max(refLh.height, refRh.height) + 1;
return ...
}
通常你不会走这样疯狂的路线,因为 JavaScript 支持以更自然的方式返回多个值:
function diameterOpt(root){
if (!root){
return {height:0, diameter:0};
}
var leftResult = diameterOpt(root.left);
var rightResult = diameterOpt(root.right);
return {
height: Math.max(leftResult.height,rightResult.height) + 1;
diameter:
Math.max(leftResult.height+rightResult.height + 1,
Math.max(leftResult.diameter, rightResult.diameter))
}
}
我在 understanding/re-writing "optimized" C 函数 here 中遇到问题,该函数用于查找二叉树的直径。我不明白它是如何跟踪高度的。我知道它使用第二个参数 height 来完成此操作,但在代码中我什至没有看到正在使用的 height 参数。我很难理解 C 中的函数,我主要用 JavaScript 编写。我能够重写页面上的所有其他功能,但没有问题。
/*The second parameter is to store the height of tree.
Initially, we need to pass a pointer to a location with value
as 0. So, function should be used as follows:
int height = 0;
struct node *root = SomeFunctionToMakeTree();
int diameter = diameterOpt(root, &height); */
int diameterOpt(struct node *root, int* height)
{
/* lh --> Height of left subtree
rh --> Height of right subtree */
int lh = 0, rh = 0;
/* ldiameter --> diameter of left subtree
rdiameter --> Diameter of right subtree */
int ldiameter = 0, rdiameter = 0;
if(root == NULL)
{
*height = 0;
return 0; /* diameter is also 0 */
}
/* Get the heights of left and right subtrees in lh and rh
And store the returned values in ldiameter and ldiameter */
ldiameter = diameterOpt(root->left, &lh);
rdiameter = diameterOpt(root->right, &rh);
/* Height of current node is max of heights of left and
right subtrees plus 1*/
*height = max(lh, rh) + 1;
return max(lh + rh + 1, max(ldiameter, rdiameter));
}
近似相当于通过引用传递(在您提供的示例中有很好的评论)将是 属性 的对象:
var heightHolder = { height:0};
var diam = diameterOpt(root, heightHolder);
console.log(heightHolder.height);
function diameterOpt(root, heightHolder){
if (!root) {
heightHolder.height = 0;
return 0;
}
var refLh = {height:0};
var refRh = {height:0};
var ldiameter = diameterOpt(root.left, refLh);
....
heightHolder.height = Math.max(refLh.height, refRh.height) + 1;
return ...
}
通常你不会走这样疯狂的路线,因为 JavaScript 支持以更自然的方式返回多个值:
function diameterOpt(root){
if (!root){
return {height:0, diameter:0};
}
var leftResult = diameterOpt(root.left);
var rightResult = diameterOpt(root.right);
return {
height: Math.max(leftResult.height,rightResult.height) + 1;
diameter:
Math.max(leftResult.height+rightResult.height + 1,
Math.max(leftResult.diameter, rightResult.diameter))
}
}