Spring JDBC 简单的例子

Question

我是 Spring 的新手，正在使用 JDBC 制作一个简单的应用程序，它从数据库中读取记录并显示在屏幕上。

package jdbcexample;

import java.util.List;

import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;

public class MainApp {

public static void main(String[] args) {
    ApplicationContext context = new ClassPathXmlApplicationContext(
            "Beans.xml");
    StudentJDBCTemplate studentjdbctemplate = (StudentJDBCTemplate) context
            .getBean("studentjdbctemplate");
    System.out.println("Listing Reocrds : ");
    List<Student> students = studentjdbctemplate.listStudents();
    for (Student record : students)
        System.out.println("id : " + record.getId() + " name : "
                + record.getName() + " password : " + record.getPassword());

}

}

这是我的 Bean.xml :

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd ">

<bean id="datasource" class="org.springframework.jdbc.datasource.DriverManagerDataSource" >
<property name="driverClassName" value="com.mysql.jdbc.Driver" />
<property name="url" value="jdbc:mysql://locallhost:3306/TEST" />
<property name="username" value="root"/>
<property name="password" value="password" />
</bean>

<bean id="studentjdbctemplate" class="jdbcexample.StudentJDBCTemplate">
    <property name="datasource" ref="datasource" />
</bean>

</beans>

所有引用的 Java 文件和 XML 文件都在同一个文件夹中，但我仍然收到此错误。你能帮我解决这个问题吗？

    log4j:WARN No appenders could be found for logger (org.springframework.context.support.ClassPathXmlApplicationContext).
log4j:WARN Please initialize the log4j system properly.
Exception in thread "main" org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [Beans.xml]; nested exception is java.io.FileNotFoundException: class path resource [Beans.xml] cannot be opened because it does not exist
    at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:341)
    at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:302)
    at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:143)
    at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:178)
    at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:149)
    at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:212)
    at org.springframework.context.support.AbstractXmlApplicationContext.loadBeanDefinitions(AbstractXmlApplicationContext.java:126)
    at org.springframework.context.support.AbstractXmlApplicationContext.loadBeanDefinitions(AbstractXmlApplicationContext.java:92)
    at org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:130)
    at org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:465)
    at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:395)
    at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:139)
    at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:83)
    at jdbcexample.MainApp.main(MainApp.java:12)
Caused by: java.io.FileNotFoundException: class path resource [Beans.xml] cannot be opened because it does not exist
    at org.springframework.core.io.ClassPathResource.getInputStream(ClassPathResource.java:141)
    at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:328)
    ... 13 more

Answer 1

在异常跟踪中class path resource [Beans.xml] cannot be opened because it does not exist

意味着类路径中缺少 Beans.xml，因此您会看到异常。确保 Beans.xml 在类路径中并且它可以正常工作。

Answer 2

Have a look at this article. 这将帮助您设置一个基本的 MAVEN Spring MVC HIbernate Sitemesh 项目

您在这里缺少的是 file not found，即 Beans.xml。

你在 web.xml 中定义了这个 class 你可以这样做

<servlet>
    <servlet-name>dispatcherServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/Beans.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

你需要这样做

<context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
            classpath:spring/application-config.xml,
            /WEB-INF/Beans.xml
        </param-value>
    </context-param>

我希望这对你有用

Answer 3

我将 Beans.xml 移动到 src 文件夹和程序运行成功。

Spring JDBC 简单的例子

Spring JDBC simple example

java

spring

jdbc