为什么 Xilinx ISE 不在状态机中接受此声明?
Why wont Xilinx ISE accept this statement in a state machine?
所以我目前正在做一个涉及 hd44780 显示器的小项目。但是因为我想编写自己的初始化序列,所以我决定使用状态机。我对 FPGA 很陌生,他们的编程来自 Java 背景。
这是我的状态机块。
我说它有效,IDE 没有显示任何错误。
always @(posedge reset)
begin
en_timeout <= 2'b00;
timeout <= 14'b00000000000000;
init <= 4'b000;
data <= 8'b00000000;
en <= 1'b1; //active low
rs <= 1'b0;
rw <= 1'b0;
state <= 4'b0000;
next_state <= 4'b0000;
debug <= 1'b0;
end
if(timeout == 0)
begin //Begin of Initiation state machine
case(state)
s0:
begin
end
s1:
begin
end
s2:
begin
end
s3:
begin
end
s4:
begin
end
s5:
begin
end
s6:
begin
end
s7:
begin
end
s8:
begin
end
s9:
begin
end
s10:
begin
end
normal:
begin
end
endcase
end //End of Initiation state machine
但是如果我在其中一个状态的开始和结束之间添加任何赋值,它会显示 "Line n: Syntax error near "<="."
例如:
case(state)
s0:
begin
state <= s1;
end
到目前为止我的 DisplayDriver 的完整代码:
module DisplayDriver(
output reg [8:0] data,
output reg en,
output reg rs,
output reg rw,
output reg debug,
input clk,
input reset
);
parameter s0=0,s1=1,s2=2,s3=3,s4=4,s5=5,s6=6,s7=7,s8=8,s9=9,s10=10,normal = 11;
reg [3:0] state; // 4 bit for max 11 combinations s0-s10 and normal
reg [3:0] state; // 4 bit for max 11 combinations s0-s10 and normal [next State]
reg [1:0] en_timeout; // 2 bit for en high to low to high cylce
reg [13:0] timeout; // 14 bit
initial
// begin init
begin
en_timeout <= 2'b00;
timeout <= 14'b00000000000000;
init <= 4'b000;
data <= 8'b00000000;
en <= 1'b1; //active low
rs <= 1'b0;
rw <= 1'b0;
state <= 4'b0000;
next_state <= 4'b0000;
debug <= 1'b0;
end
// end of init
always @(posedge clk)
//begin of everything that needs the clock
begin
if(en_timeout > 0) //begin timeout stack
begin
en_timeout <= en_timeout -1;
en <= ~en;// if en_timeout = 2 -> en = 0; if en_timeout = 1 -> en = 1;
end
else if (timeout > 0) timeout <= timeout -1; //end timeout stack
if(timeout == 0)state <= next_state;
end //end of everything that needs the clock
always @(posedge reset)
begin
en_timeout <= 2'b00;
timeout <= 14'b00000000000000;
init <= 4'b000;
data <= 8'b00000000;
en <= 1'b1; //active low
rs <= 1'b0;
rw <= 1'b0;
state <= 4'b0000;
next_state <= 4'b0000;
debug <= 1'b0;
end
if(timeout == 0)
begin //Begin of Initiation state machine
case(state)
s0:
begin
end
s1:
begin
end
s2:
begin
end
s3:
begin
end
s4:
begin
end
s5:
begin
end
s6:
begin
end
s7:
begin
end
s8:
begin
end
s9:
begin
end
s10:
begin
end
normal:
begin
end
endcase
end //End of Initiation state machine
endmodule
有谁知道它为什么会这样?
我假设您正在尝试为 "state" 合成一个寄存器,在这种情况下更新“<=”需要始终在内部(@posedge clk)。
所以我目前正在做一个涉及 hd44780 显示器的小项目。但是因为我想编写自己的初始化序列,所以我决定使用状态机。我对 FPGA 很陌生,他们的编程来自 Java 背景。
这是我的状态机块。
我说它有效,IDE 没有显示任何错误。
always @(posedge reset)
begin
en_timeout <= 2'b00;
timeout <= 14'b00000000000000;
init <= 4'b000;
data <= 8'b00000000;
en <= 1'b1; //active low
rs <= 1'b0;
rw <= 1'b0;
state <= 4'b0000;
next_state <= 4'b0000;
debug <= 1'b0;
end
if(timeout == 0)
begin //Begin of Initiation state machine
case(state)
s0:
begin
end
s1:
begin
end
s2:
begin
end
s3:
begin
end
s4:
begin
end
s5:
begin
end
s6:
begin
end
s7:
begin
end
s8:
begin
end
s9:
begin
end
s10:
begin
end
normal:
begin
end
endcase
end //End of Initiation state machine
但是如果我在其中一个状态的开始和结束之间添加任何赋值,它会显示 "Line n: Syntax error near "<="."
例如:
case(state)
s0:
begin
state <= s1;
end
到目前为止我的 DisplayDriver 的完整代码:
module DisplayDriver(
output reg [8:0] data,
output reg en,
output reg rs,
output reg rw,
output reg debug,
input clk,
input reset
);
parameter s0=0,s1=1,s2=2,s3=3,s4=4,s5=5,s6=6,s7=7,s8=8,s9=9,s10=10,normal = 11;
reg [3:0] state; // 4 bit for max 11 combinations s0-s10 and normal
reg [3:0] state; // 4 bit for max 11 combinations s0-s10 and normal [next State]
reg [1:0] en_timeout; // 2 bit for en high to low to high cylce
reg [13:0] timeout; // 14 bit
initial
// begin init
begin
en_timeout <= 2'b00;
timeout <= 14'b00000000000000;
init <= 4'b000;
data <= 8'b00000000;
en <= 1'b1; //active low
rs <= 1'b0;
rw <= 1'b0;
state <= 4'b0000;
next_state <= 4'b0000;
debug <= 1'b0;
end
// end of init
always @(posedge clk)
//begin of everything that needs the clock
begin
if(en_timeout > 0) //begin timeout stack
begin
en_timeout <= en_timeout -1;
en <= ~en;// if en_timeout = 2 -> en = 0; if en_timeout = 1 -> en = 1;
end
else if (timeout > 0) timeout <= timeout -1; //end timeout stack
if(timeout == 0)state <= next_state;
end //end of everything that needs the clock
always @(posedge reset)
begin
en_timeout <= 2'b00;
timeout <= 14'b00000000000000;
init <= 4'b000;
data <= 8'b00000000;
en <= 1'b1; //active low
rs <= 1'b0;
rw <= 1'b0;
state <= 4'b0000;
next_state <= 4'b0000;
debug <= 1'b0;
end
if(timeout == 0)
begin //Begin of Initiation state machine
case(state)
s0:
begin
end
s1:
begin
end
s2:
begin
end
s3:
begin
end
s4:
begin
end
s5:
begin
end
s6:
begin
end
s7:
begin
end
s8:
begin
end
s9:
begin
end
s10:
begin
end
normal:
begin
end
endcase
end //End of Initiation state machine
endmodule
有谁知道它为什么会这样?
我假设您正在尝试为 "state" 合成一个寄存器,在这种情况下更新“<=”需要始终在内部(@posedge clk)。